例3-2 判断奇偶

判断奇偶

程序核心——判断语句

程序

#include<stdio.h>
int main()
{
	int number; 
	
	printf("Enter number:");
	scanf("%d",&number);
	if(number%2==0)//两数相等 
		printf("The number is even.
");
	else
		printf("The number is odd.
");
	return 0; 
 } 

结果

Enter number:3
The number is odd.

--------------------------------
Process exited after 1.916 seconds with return value 0
请按任意键继续. . .

分析

重点：判断语句，注意判断条件是否存在遗漏