Given an integer array nums
, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.
Example:
Input: [-2,1,-3,4,-1,2,1,-5,4], Output: 6 Explanation: [4,-1,2,1] has the largest sum = 6.
Follow up:
If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
方法一:不过这个方法对全是负数时,不成立;
class Solution { public: int maxSubArray(vector<int>& nums) { int ans=nums[0],sum=0; for(int i=0; i<nums.size();i++){ sum+=nums[i]; ans=max(ans,sum); sum=max(sum,0); } return ans; } };
//Idea is very simple. Basically, keep adding each integer to the sequence until the sum drops below 0.
//If sum is negative, then should reset the sequence.