• bzoj5063


    平衡树

    6个操作做完当然GG了,其实只有两个操作,翻转[A+1,A+B],把这个区间放到C的后面,那么就是基本splay操作了,可是好久没打,又GG了,splay函数写错了。。。

    #include<bits/stdc++.h>
    using namespace std;
    const int N = 1e5 + 5;
    namespace IO 
    {
        const int Maxlen = N * 50;
        char buf[Maxlen], *C = buf;
        int Len;
        inline void read_in()
        {
            Len = fread(C, 1, Maxlen, stdin);
            buf[Len] = '';
        }
        inline void fread(int &x) 
        {
            x = 0;
            int f = 1;
            while (*C < '0' || '9' < *C) { if(*C == '-') f = -1; ++C; }
            while ('0' <= *C && *C <= '9') x = (x << 1) + (x << 3) + *C - '0', ++C;
            x *= f;
        }
        inline void fread(long long &x) 
        {
            x = 0;
            long long f = 1;
            while (*C < '0' || '9' < *C) { if(*C == '-') f = -1; ++C; }
            while ('0' <= *C && *C <= '9') x = (x << 1) + (x << 3) + *C - '0', ++C;
            x *= f;
        }
        inline void read(int &x)
        {
            x = 0;
            int f = 1; char c = getchar();
            while(c < '0' || c > '9') { if(c == '-') f = -1; c = getchar(); }
            while(c >= '0' && c <= '9') { x = (x << 1) + (x << 3) + c - '0'; c = getchar(); }
            x *= f;
        }
        inline void read(long long &x)
        {
            x = 0;
            long long f = 1; char c = getchar();
            while(c < '0' || c > '9') { if(c == '-') f = -1; c = getchar(); }
            while(c >= '0' && c <= '9') { x = (x << 1ll) + (x << 3ll) + c - '0'; c = getchar(); }
            x *= f;
        } 
    } using namespace IO;
    struct node {
        int f, rev, sz;
        int ch[2];
    } t[N];
    int n, m, root;
    int ans[N], size[N];
    void update(int x)
    {
        t[x].sz = t[t[x].ch[0]].sz + t[t[x].ch[1]].sz + 1;
    }
    bool wh(int x) 
    {
        return x == t[t[x].f].ch[1];
    }
    void pushdown(int x)
    {
        if(!t[x].rev) return;
        t[t[x].ch[0]].rev ^= 1;
        t[t[x].ch[1]].rev ^= 1;
        swap(t[x].ch[0], t[x].ch[1]);
        t[x].rev = 0;
    }
    void up(int x)
    {
        if(t[x].f) up(t[x].f);
        pushdown(x);
    }
    int build(int l, int r, int f)
    {
        if(l > r) return 0;
        int mid = (l + r) >> 1; 
        t[mid].f = f;
        t[mid].ch[0] = build(l, mid - 1, mid);
        t[mid].ch[1] = build(mid + 1, r, mid);
        update(mid);
        return mid;
    }
    void rotate(int x)
    {
        int f = t[x].f, w = wh(x);
        t[x].f = t[f].f;
        t[t[f].f].ch[wh(f)] = x;
        t[f].ch[w] = t[x].ch[w ^ 1];
        t[t[x].ch[w ^ 1]].f = f;
        t[x].ch[w ^ 1] = f;
        t[f].f = x;
        update(f);
        update(x);
    }
    inline void splay(int x, int tar)
    {
        for(; t[x].f != tar; rotate(x))
            if(t[t[x].f].f != tar) 
                rotate(wh(x) == wh(t[x].f) ? t[x].f : x);
        if(!tar) root = x;      
    }
    int find(int x, int k)
    {
        pushdown(x);
        if(t[t[x].ch[0]].sz + 1 == k) return x;
        if(k <= t[t[x].ch[0]].sz) return find(t[x].ch[0], k);
        return find(t[x].ch[1], k - t[t[x].ch[0]].sz - 1);
    }
    int split(int l, int r)
    {
        int x = find(root, l - 1), y = find(root, r + 1);
        splay(x, 0);
        splay(y, root);
        return y;
    }
    void dfs(int u)
    {
        if(!u) return;
        pushdown(u);
        dfs(t[u].ch[0]);
        ans[++ans[0]] = u;
        dfs(t[u].ch[1]);
    }
    int main()
    {
        read_in();
        fread(n);
        fread(m);
        root = build(1, n + 2, 0);
        while(m--)
        {
            int A, B, C;
            fread(A);
            fread(B);
            fread(C);
            int x = split(A + 2, A + B + 1), y = t[x].ch[0];
            t[y].rev ^= 1;
            t[y].f = t[x].ch[0] = 0;
            update(x);
            update(t[x].f);
            int z = split(C + 2, C + 1);
            t[y].f = z;
            t[z].ch[0] = y;
            update(z);
            update(t[z].f);
        }
        dfs(root);
        for(int i = 2; i < ans[0]; ++i) printf("%d ", ans[i] - 1);
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/19992147orz/p/7868110.html
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