• Oracle 数据库基础


    create table student(
    sno varchar2(10) primary key,
    sname varchar2(20),
    sage number(2),
    ssex varchar2(5)
    );
    
    create table teacher(
    tno varchar2(10) primary key,
    tname varchar2(20)
    );
    
    create table course(
    cno varchar2(10),
    cname varchar2(20),
    tno varchar2(20),
    constraint pk_course primary key (cno,tno)
    );
    
    create table sc(
    sno varchar2(10),
    cno varchar2(10),
    score number(4,2), 
    constraint pk_sc primary key (sno,cno)
    );
    
    
    
    
    /*******初始化学生表的数据******/
    insert into student values ('s001','张三',23,'男');
    insert into student values ('s002','李四',23,'男');
    insert into student values ('s003','吴鹏',25,'男');
    insert into student values ('s004','琴沁',20,'女');
    insert into student values ('s005','王丽',20,'女');
    insert into student values ('s006','李波',21,'男');
    insert into student values ('s007','刘玉',21,'男');
    insert into student values ('s008','萧蓉',21,'女');
    insert into student values ('s009','陈萧晓',23,'女');
    insert into student values ('s010','陈美',22,'女');
    insert into student values ('s011','杨超越',18,'女');
    insert into student values ('s012','孙超越',21,'女');
    
    /******************初始化教师表***********************/
    insert into teacher values ('t001', '刘阳');
    insert into teacher values ('t002', '谌燕');
    insert into teacher values ('t003', '胡明星');
    
    /***************初始化课程表****************************/
    insert into course values ('c001','J2SE','t002');
    insert into course values ('c002','Java Web','t002');
    insert into course values ('c003','SSH','t001');
    insert into course values ('c004','Oracle','t001');
    insert into course values ('c005','SQL SERVER 2005','t003');
    insert into course values ('c006','C#','t003');
    insert into course values ('c007','JavaScript','t002');
    insert into course values ('c008','DIV+CSS ','t001');
    insert into course values ('c009','PHP ','t003');
    insert into course values ('c010','EJB3.0','t002');
    
    /***************初始化成绩表***********************/
    insert into sc values ('s001','c001',78.9);
    insert into sc values ('s002','c001',80.9);
    insert into sc values ('s003','c001',81.9);
    insert into sc values ('s004','c001',60.9);
    insert into sc values ('s001','c002',82.9);
    insert into sc values ('s002','c002',72.9);
    insert into sc values ('s003','c002',81.9);
    insert into sc values ('s001','c003','59');
    
    
    /*
    Question:
    
    0.   查询所有表中的信息
    */
    select * from student;
    select * from teacher;
    select * from course;
    select * from sc;
    
    
    
    
    --1、查询姓“李”的学生的详细信息
    -- 这是一个模糊查询
    -- 精确查询select * from student where sname ='李**'
    select * from student where sname like '李%';
    --% 是通配符
    
    
    --2、查询20-23岁的男同学有多少个
    /*   分解一下查询条件
         年龄   20~23
         性别是 男
    
    
         查询的结果是一个统计结果
    */
    select count(*) from student where ssex='男' and sage>=20 and sage<=23;
    /*
    统计函数 count(*)
    and  同时要求满足
    */
    
    --3、查询姓“刘”的老师有多少个
    select count(*) from teacher where tname like '刘%';
    
    --4、查询男生、女生人数(一条SQL)
    select count(*) from student where ssex ='男';
    select count(*) from student where ssex ='女';
    
    /*
    分组查询  group by
    你要查什么  在那个地方查  你分组条件是什么
    */
    
    select count(*) from student group by ssex;
    
    
    
    --5、查询'刘阳'老师所教的课程
    --通过表的查询结果来查询
    --连表查询  join
    -- in  包含于()
    select * from course where tno in  (select tno from teacher where tname='刘阳');
    
    
    --6、查找学员编号为's004','s007','s008'的学生信息
    --精确查找
    select * from student where sno ='s004';
    select * from student where sno in  ('s004','s007','s008');
    
    
    --7、查找教'Oracle'课程的老师
    select * from teacher where tno in (select tno from course where cname='SSH');
    
    --8、查找成绩低于60分的课程名称
    select cname from course where cno in ( select cno from sc where score<60) ;
    
    --9、查找成绩良好(分数>80)的学员名称和课程名称
    -- select sname from student  where ?
    -- select cname from course   where ?
    -- select ? from sc where score >80
    select 
    (
        select sname 
        from student  
        where student.sno=sc.sno) as '姓名',
    (    select  
        from course   
        where course.cno=sc.cno
    ) as '科目'
    from sc 
    where score >80;
    -- 上面这种是最老土的做法
    
    select student.sname ,course.cname from student,course,sc 
    where score >80 and student.sno=sc.sno and course.cno=sc.cno;
    
    --10、查询平均成绩大于60 分的同学的学号和平均成绩
    /*
    avg() 求平均值
    */
    
    select sno,avg(score) 
    from  sc
    group by sno having avg(score)>60;
    
    /*
    根据分组查询学号平均成绩大于60分 
    再来查对应的信息
    
    */
    
    --11、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分
    /*
    max() 求最大值
    min() 求最小值
    */
    
    select cno ,max(score),min(score) 
    from sc
    group by cno
    
    
    --12、查询同名同姓学生名单,并统计同名人数
    select  sname,count(*) 
    from student
    group by sname;
    
    --13、1999 年出生的学生名单(注:Student 表中Sage 列的类型是number)
    select sname from student where 2020-sage=1999;
    --select sname from student where YEAR(getdate())-sage=1999;
    /*
    where 两种写法  1 写死 
                   2 获取当前时间
    */
    
    14、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列
    select cno , avg(score)
    from sc
    group by cno 
    order by avg(score),cno desc;
    
    /*
    1 做一个分组查询 group by
    2 做一个排序 order by
    
    */
    
    --15、查询课程名称为“Oracle”,且分数低于60 的学生姓名和分数
    --select * from course where cname='Oracle'
    --select * from  sc where score <60
    
    select (select sname from student  where student.sno=sc.sno), score
    from  sc
    where  cno in (select cno  from course where cname='Oracle') and score<60;
    
    
    16、查询所有学生的选课情况;
    
    select (select sname from student where student.sno=sc.sno),
            (select cname from course where course.cno=sc.cno)
    from sc;
    
    
    17、查询不及格的课程,并按课程号从大到小排列
    
    select sno from sc where score<60 order by sno DESC;
    
    18、查询课程编号为c001 且课程成绩在80 分以上的学生的学号和姓名;
    
    select sno,sname from student 
    where sno in(
        select sno 
        from sc 
        where cno='c001' 
        and
        score >=80
          )
        ;
    
    19、求选了课程的学生人数
    
    select count(*) from student where exists(
    select * from sc where student.sno=sc.sno);
    
    20、查询各个课程及相应的选修人数
    select cno ,count(*) from sc group by cno;
    
    21、查询不同课程成绩相同的学生的学号、课程号、学生成绩
    select a.* from sc a ,sc b where a.score=b.score and a.cno<>b.cno
    22、检索“c001”课程分数小于100,按分数降序排列的同学学号
    select  sno from sc  where cno='c001' and score<100 order by score; 
    23、查询“c001”课程比“c002”课程成绩高的所有学生的学号;
    select * from student st
    join sc a on st.sno=a.sno
    join sc b on st.sno=b.sno
    where a.cno='c002' and b.cno='c001' and a.score < b.score;
    24、查询没学过“谌燕”老师课的同学的学号、姓名;
    select sno ,sname from student where sno not in (select sno from sc where cno in
    (select cno from course where tno in (select tno from teacher where tname='谌燕') ));
    
    25、按各科平均成绩从低到高和及格率的百分数从高到低顺序
    select cno,avg(score),sum(case when score>=60 then 1 else 0 end)/count(*)
    as 及格率
    from sc group by cno
    order by avg(score) , 及格率 desc;
    每个人都是在努力的路上,别因为别人的误解而放弃,,术业有专攻,如是而已。
  • 相关阅读:
    使用Application Insights 做分析
    UWP中GridView右击选中的实现
    Bing Map
    UWP深入学习六:Build better apps: Windows 10 by 10 development series
    从上往下打印二叉树
    二叉树中和为某一值的路径
    二叉树的镜像
    树的子结构
    由前序遍历和中序遍历构建二叉树
    二叉树常见题目
  • 原文地址:https://www.cnblogs.com/16699qq/p/13153410.html
Copyright © 2020-2023  润新知