• java.util.LinkedList源码分析


    public class LinkedList<E>
        extends AbstractSequentialList<E>
        implements List<E>, Deque<E>, Cloneable, java.io.Serializable

    LinkedList是一个双向链表的实现,允许所有的元素,包括null。

    对于index操作,会从链头到链尾地搜索,即使它靠近一个特殊索引位置。

    非线程安全的,在多线程环境下,需要外部同步或调用Collections.synchronizedList(new LinkedList(...));获得一个线程安全的链表。

    迭代器是快速失败的。

    3个实例变量

    //链表大小
    transient int size = 0;
    
    //链头
    transient Node<E> first;
    
    //链尾
    transient Node<E> last;

    2个构造器

    //空链表
    public LinkedList() {
    }
    
    //根据c创建链表,链表的顺序取决于c的iterator返回元素的顺序
    public LinkedList(Collection<? extends E> c) {
        this();
        addAll(c);
    }

    操作

    //返回链表第一个元素
    public E getFirst() {
            final Node<E> f = first;
            if (f == null)
                throw new NoSuchElementException();
            return f.item;
    }
    
    //返回链表最后一个元素
    public E getLast() {
            final Node<E> l = last;
            if (l == null)
                throw new NoSuchElementException();
            return l.item;
    }
    
    //删除第一个元素,返回值是第一个元素的值
    public E removeFirst() {
            final Node<E> f = first;
            if (f == null)
                throw new NoSuchElementException();
            return unlinkFirst(f);
    }
    
    //删除最后一个元素,返回值是最后一个元素
    public E removeLast() {
            final Node<E> l = last;
            if (l == null)
                throw new NoSuchElementException();
            return unlinkLast(l);
    }
    
    //插入一个元素作为链头
    public void addFirst(E e) {
            linkFirst(e);
    }
    
    //插入一个元素作为链尾
    public void addLast(E e) {
            linkLast(e);
    }
    
    //判断链表是否含有o
    public boolean contains(Object o) {
            return indexOf(o) != -1;
    }
    
    //返回链表大小
    public int size() {
            return size;
    }
    
    //与addLast的效果一样,在链尾添加一个元素
    public boolean add(E e) {
            linkLast(e);
            return true;
    }
    
    //删除从链头开始遇到第一个与o等同的元素,如果返回true,表示删除成功
    public boolean remove(Object o) {
            if (o == null) {
                for (Node<E> x = first; x != null; x = x.next) {
                    if (x.item == null) {
                        unlink(x);
                        return true;
                    }
                }
            } else {
                for (Node<E> x = first; x != null; x = x.next) {
                    if (o.equals(x.item)) {
                        unlink(x);
                        return true;
                    }
                }
            }
            return false;
    }
    
    //将c集合的元素添加到链表,插入顺序取决于c的iterator返回的元素顺序
    public boolean addAll(Collection<? extends E> c) {
            return addAll(size, c);
    }
    
    //在index位置开始将c集合的元素添加到链表,插入顺序取决于c的iterator返回的元素顺序
    public boolean addAll(int index, Collection<? extends E> c) {
            checkPositionIndex(index);
    
            Object[] a = c.toArray();
            int numNew = a.length;
            if (numNew == 0)
                return false;
    
            Node<E> pred, succ;
            if (index == size) {
                succ = null;
                pred = last;
            } else {
                succ = node(index);
                pred = succ.prev;
            }
    
            for (Object o : a) {
                @SuppressWarnings("unchecked") E e = (E) o;
                Node<E> newNode = new Node<>(pred, e, null);
                if (pred == null)
                    first = newNode;
                else
                    pred.next = newNode;
                pred = newNode;
            }
    
            if (succ == null) {
                last = pred;
            } else {
                pred.next = succ;
                succ.prev = pred;
            }
    
            size += numNew;
            modCount++;
            return true;
    }
    
    //清空链表
    public void clear() {
            // Clearing all of the links between nodes is "unnecessary", but:
            // - helps a generational GC if the discarded nodes inhabit
            //   more than one generation
            // - is sure to free memory even if there is a reachable Iterator
            for (Node<E> x = first; x != null; ) {
                Node<E> next = x.next;
                x.item = null;
                x.next = null;
                x.prev = null;
                x = next;
            }
            first = last = null;
            size = 0;
            modCount++;
    }
    
    //获取在index位置的元素
    public E get(int index) {
            checkElementIndex(index);
            return node(index).item;
    }
    
    //将index位置的元素的值修改为element
    public E set(int index, E element) {
            checkElementIndex(index);
            Node<E> x = node(index);
            E oldVal = x.item;
            x.item = element;
            return oldVal;
    }
    
    //在index位置插入一个element元素
    public void add(int index, E element) {
            checkPositionIndex(index);
    
            if (index == size)
                linkLast(element);
            else
                linkBefore(element, node(index));
    }
    
    //删除index位置的元素,返回值是被删除元素的值
    public E remove(int index) {
            checkElementIndex(index);
            return unlink(node(index));
    }
    
    //返回从链头到链尾第一个遇到与o等同的元素所在的位置,如果不存在返回-1
    public int indexOf(Object o) {
            int index = 0;
            if (o == null) {
                for (Node<E> x = first; x != null; x = x.next) {
                    if (x.item == null)
                        return index;
                    index++;
                }
            } else {
                for (Node<E> x = first; x != null; x = x.next) {
                    if (o.equals(x.item))
                        return index;
                    index++;
                }
            }
            return -1;
    }
    
    //返回从链尾到链头第一个遇到与o等同的元素所在的位置,如果不存在返回-1
    public int lastIndexOf(Object o) {
            int index = size;
            if (o == null) {
                for (Node<E> x = last; x != null; x = x.prev) {
                    index--;
                    if (x.item == null)
                        return index;
                }
            } else {
                for (Node<E> x = last; x != null; x = x.prev) {
                    index--;
                    if (o.equals(x.item))
                        return index;
                }
            }
            return -1;
    }
    
    //返回链头元素值
    public E peek() {
            final Node<E> f = first;
            return (f == null) ? null : f.item;
    }
    
    //返回链头元素值,如果链表为空,抛出NoSuchElementException
    public E element() {
            return getFirst();
    }
    
    //返回并删除链头元素值
    public E poll() {
            final Node<E> f = first;
            return (f == null) ? null : unlinkFirst(f);
    }
    
    //返回并删除链头元素值,如果链表为 空,抛出NoSuchElementException
    public E remove() {
            return removeFirst();
    }
    
    //在链尾添加元素e
    public boolean offer(E e) {
            return add(e);
    }
    
    //在链头插入元素e
    public boolean offerFirst(E e) {
            addFirst(e);
            return true;
    }
    
    //在链尾插入元素e
    public boolean offerLast(E e) {
            addLast(e);
            return true;
    }
    
    //返回链头元素,如果链表为空,返回null
    public E peekFirst() {
            final Node<E> f = first;
            return (f == null) ? null : f.item;
    }
    
    //返回链尾元素,如果链表为空,返回null
    public E peekLast() {
            final Node<E> l = last;
            return (l == null) ? null : l.item;
    }
    
    //返回并删除链头元素
    public E pollFirst() {
            final Node<E> f = first;
            return (f == null) ? null : unlinkFirst(f);
    }
    
    //返回并删除链尾元素
    public E pollLast() {
            final Node<E> l = last;
            return (l == null) ? null : unlinkLast(l);
    }
    
    //在链头插入元素e
    public void push(E e) {
            addFirst(e);
    }
    
    //删除并返回链头元素
    public E pop() {
            return removeFirst();
    }
    
    //删除从链头到结尾第一个遇到与o等同的元素,如果不存在,什么也不做
    public boolean removeFirstOccurrence(Object o) {
            return remove(o);
    }
    
    //删除从链尾到链头第一个遇到与o等同的元素,如果不存在,什么也不做
    public boolean removeLastOccurrence(Object o) {
            if (o == null) {
                for (Node<E> x = last; x != null; x = x.prev) {
                    if (x.item == null) {
                        unlink(x);
                        return true;
                    }
                }
            } else {
                for (Node<E> x = last; x != null; x = x.prev) {
                    if (o.equals(x.item)) {
                        unlink(x);
                        return true;
                    }
                }
            }
            return false;
    }
    
    //返回一个列表迭代器,可以向前或向后迭代,index指定起始位置
    public ListIterator<E> listIterator(int index) {
            checkPositionIndex(index);
            return new ListItr(index);
    }
    
    //返回从链尾开始的迭代器,在ListIterator的基础上实现的
    public Iterator<E> descendingIterator() {
            return new DescendingIterator();
    }

    支持clone

    public Object clone() {
            LinkedList<E> clone = superClone();
    
            // Put clone into "virgin" state
            clone.first = clone.last = null;
            clone.size = 0;
            clone.modCount = 0;
    
            // Initialize clone with our elements
            for (Node<E> x = first; x != null; x = x.next)
                clone.add(x.item);
    
            return clone;
    }

    支持序列化和反序列化

    private void writeObject(java.io.ObjectOutputStream s)
            throws java.io.IOException {
            // Write out any hidden serialization magic
            s.defaultWriteObject();
    
            // Write out size
            s.writeInt(size);
    
            // Write out all elements in the proper order.
            for (Node<E> x = first; x != null; x = x.next)
                s.writeObject(x.item);
    }
    
    private void readObject(java.io.ObjectInputStream s)
            throws java.io.IOException, ClassNotFoundException {
            // Read in any hidden serialization magic
            s.defaultReadObject();
    
            // Read in size
            int size = s.readInt();
    
            // Read in all elements in the proper order.
            for (int i = 0; i < size; i++)
                linkLast((E)s.readObject());
    }
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  • 原文地址:https://www.cnblogs.com/13jhzeng/p/5812127.html
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