• mysql中相关,无关子查询,表与表之间的关系以及编码和乱码的解决


    ※MySQL中的字符编码(注意,utf8中没有'-',跟Java中不一样)
    SHOW VARIABLES; //查看系统变量
    //查询字符编码相关的系统变量
    SHOW VARIABLES WHERE variable_name LIKE 'character%';

    解决MySQK的中文乱码:
    character_set_client,character_set_connection和character_set_results这三者必须一致(GBK,GB2312,UTF8这三者都可以,但若采用其中一种则3个变量都要设这种)

    设置字符编码的系统变量:
    set character_set_client=utf8; //独立设置某个变量
    set names utf8; //同时设置3个:client、 connection和results

    ※其实,MySQL中的数据库、数据表 甚至 数据列 都可以有自己的编码,只是我们一般不专门设置。---从SQLyog中的更改表结构中可以查看出

    INSERT INTO stud VALUES(4,'湖南',20);

    CREATE TABLE person(
    id INT,
    NAME VARCHAR(30),
    age INT
    );

    CREATE TABLE car(
    id INT PRIMARY KEY, //不允许重复,也不允许NULL
    NAME VARCHAR(30),
    NO INT UNIQUE //不允许重复,允许NULL但最多只能一个
    );
    //除了在创建表时如上的方式直接指定主键,也可以通过修改表的方式单独创建主键:
    ALTER TABLE person ADD CONSTRAINT person_pk PRIMARY KEY(id);
    ALTER TABLE person ADD CONSTRAINT UNIQUE (NAME); //为name字段添加一个unique约束

    //添加和删除unique约束 --通过约束名称
    ALTER TABLE person ADD CONSTRAINT UNIQUE uniq_nm (NAME);
    DROP INDEX uniq_nm ON person;


    //删除主键
    ALTER TABLE person DROP PRIMARY KEY;


    //有关性别字段,比较好的表结构。DATE类型勉强用,建议不要用DATETIME。为考虑兼容性,最好用CHAR(19),VARCHAR(19) //datetime格式: 2016-11-11 23:24:09
    CREATE TABLE s(
    id INT,
    sex CHAR(1) DEFAULT '0',
    birth DATE
    );
    INSERT INTO s(id,birth) VALUES(3,'2008/8/8'); //因为sex字段设了default,所以该字段不手动赋值时,由默认值0来赋
    按理,date的规范格式是"yyyy-MM-dd",但我们给其他格式如"yyyy/M/d"时,MySQL也会帮我们自动转换成规范格式。


    //有关性别字段的显示
    学习一个SQL语法: 手册-->函数和操作符-->控制流程函数-->Case-When

    SELECT id, (CASE sex WHEN '0' THEN '女' WHEN '1' THEN '男' ELSE '其它' END) AS 性别, birth FROM s;


    ※1无关子查询
    需求:查询具有同龄人的学生
    SELECT * FROM stud WHERE age IN(20,22,23); //过渡版:"20,22,23" 写死了
    SELECT age FROM stud GROUP BY age HAVING COUNT(age)>=2; //这句可以动态输出:20,22,23
    综上:
    SELECT * FROM stud WHERE age IN( SELECT age FROM stud GROUP BY age HAVING COUNT(age)>=2 ) ORDER BY age ASC;

    ※2相关子查询(子查询中用到了外面的查询结果表)
    需求:查询具有同龄人且年龄大于22的学生
    SELECT * FROM stud as s2 WHERE age IN( SELECT age FROM stud where s2.age>22 GROUP BY age HAVING COUNT(age)>=2 ) ORDER BY age ASC;

    select ... from ... where ... in( 子查询 ) order by ... asc(desc)
    select ... from ... where ... group by ... having ...


    ※表与表之间的关系(1对1)
    1、
    CREATE TABLE person(
    id INT,
    NAME VARCHAR(10),
    sex CHAR(1),
    wife INT,
    husband INT
    );
    INSERT INTO person VALUES(1,'小花','0',0,3);
    INSERT INTO person VALUES(2,'玉芬','0',0,4);
    INSERT INTO person VALUES(3,'张三','1',1,0);
    INSERT INTO person VALUES(4,'李四','1',2,0);
    INSERT INTO person VALUES(5,'王五','1',0,0);


    SELECT * FROM person WHERE sex='0';
    SELECT * FROM person WHERE sex='1';

    CREATE VIEW w AS SELECT * FROM person WHERE sex='0';
    CREATE VIEW m AS SELECT * FROM person WHERE sex='1';

    CREATE VIEW w2 AS SELECT id,NAME,sex,husband FROM person WHERE sex='0';
    CREATE VIEW m2 AS SELECT id,NAME,sex,wife FROM person WHERE sex='1';


    SELECT w.name AS wn, m.name AS mn FROM w INNER JOIN m ON w.husband=m.id AND m.wife=w.id; (通过表与表之间的内连接进行查询)

    SELECT * FROM w INNER JOIN m ON w.husband=m.id AND m.wife=w.id;

  • 相关阅读:
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    ORA-00923: FROM keyword not found where expected
    ORA-00933: SQL command not properly ended
    ORA_12514:TNS:listener does not currently know of service requested in connect descriptor
    ORA-00918: column ambiguously defined
    ORA-01789: 查询块具有不正确的结果列数
    ORA-01789: query block has incorrect number of result columns
    ORA-01747
    ORA-01843: not a valid month
    ORA-00904: "I_LEVEL": invalid identifier
  • 原文地址:https://www.cnblogs.com/1314wamm/p/6016513.html
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