• cf #309a A


    A - Kyoya and Photobooks
    Time Limit:2000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u
    Submit Status

    Description

    Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the photos in the booklet in order. He now wants to sell some "special edition" photobooks, each with one extra photo inserted anywhere in the book. He wants to make as many distinct photobooks as possible, so he can make more money. He asks Haruhi, how many distinct photobooks can he make by inserting one extra photo into the photobook he already has?

    Please help Haruhi solve this problem.

    Input

    The first line of input will be a single string s (1 ≤ |s| ≤ 20). String s consists only of lowercase English letters.

    Output

    Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make.

    Sample Input

    Input
    a
    Output
    51
    Input
    hi
    Output
    76

    Hint

    In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets.

    /*************************************************************************
        > File Name: code/cf/309/A.cpp
        > Author: 111qqz
        > Email: rkz2013@126.com 
        > Created Time: 2015年08月02日 星期日 18时06分27秒
     ************************************************************************/
    
    #include<iostream>
    #include<iomanip>
    #include<cstdio>
    #include<algorithm>
    #include<cmath>
    #include<cstring>
    #include<string>
    #include<map>
    #include<set>
    #include<queue>
    #include<vector>
    #include<stack>
    #define y0 abc111qqz
    #define y1 hust111qqz
    #define yn hez111qqz
    #define j1 cute111qqz
    #define tm crazy111qqz
    #define lr dying111qqz
    using namespace std;
    #define REP(i, n) for (int i=0;i<int(n);++i)  
    typedef long long LL;
    typedef unsigned long long ULL;
    const int inf = 0x7fffffff;
    int main()
    {
        string st;
        cin>>st;
        int len = st.length();
        cout<<(len+1)*26-len;
        return 0;
    }
  • 相关阅读:
    vue+ajax+bootstrap+python实现增删改
    django笔记
    阻止冒泡事件的另一种写法
    c# 字符串的内存分配和驻留池( 转 )
    c# 几种深拷贝方式的比较
    JS 常用函数
    Web Api 过滤器之 AuthorizationFilter 验证过滤器
    c# await 到底等待的是什么?
    ( 转 ) CORS 有一次 OPTIONS 请求的原理
    Web Api 过滤器之 ExceptionFilter 异常过滤器
  • 原文地址:https://www.cnblogs.com/111qqz/p/4696478.html
Copyright © 2020-2023  润新知