• 最小生成树 Building a Space Station 三维 作为范二青年我用了克鲁斯算法,而且很悲剧的是我很无奈的用g++交了一中午,然后WA= =。。。


    Building a Space Station

    题目连接:http://poj.org/problem?id=2031

    没有什么难点,唯一要注意的是重复路径和相交的情况,但是前一点用克鲁斯基本可以无视~

    今天涨姿势了~PKU上用G++输出时printf不能用lf得用f以前有个好习惯都用f。。。

    View Code
    加一个prim的写法
    View Code
    #include <stdio.h>
    #include <string.h>
    #include <math.h>
    #define maxn 1000000
    struct node
    {
        double x,y,z,r;
    }degree[105];
    double map[105][105];
    
    double res(int i,int j)
    {
        double x,y,z;
        x = (degree[i].x-degree[j].x)*(degree[i].x-degree[j].x);
        y = (degree[i].y-degree[j].y)*(degree[i].y-degree[j].y);
        z = (degree[i].z-degree[j].z)*(degree[i].z-degree[j].z);
        double dis;
        dis = sqrt(x+y+z);
        if(dis > degree[i].r+degree[j].r)
        return dis-degree[i].r-degree[j].r;
        else
        return 0;
    }
    double prim(int n)
    {
        int vis[105] = {0};
        double dis[105] = {0};
    
        int i,j,pre;
        double min,ans;
    
        ans = 0;
    
        vis[1] = 1;
        for(i =2;i <= n;i++)
        dis[i] = map[1][i];
    
        for(i = 2;i <= n;i++)
        {
            min = maxn;
            for(j =2;j <= n;j++)//寻找最短的那一条~
            {
                if(!vis[j] && min > dis[j])
                min = dis[j],pre = j;
            }
    
            vis[pre] = 1;
            ans += min;
    
            for(j = 2;j <= n;j++)//寻找下一个点,更新值
            if(!vis[j] && dis[j] > map[pre][j])
            dis[j] = map[pre][j];
        }
        return ans;
    }
    int main()
    {
        int n,i,j;
        while(scanf("%d",&n)&&n)
        {
            for(i = 1;i <= n;i++)
            scanf("%lf %lf %lf %lf",&degree[i].x,&degree[i].y,&degree[i].z,&degree[i].r);
    
            for(i = 1;i <= n;i++)
            for(j = i+1;j <= n;j++)
            map[j][i] = map[i][j] = res(i,j);
    
            printf("%.3f\n",prim(n));
        }
    }

     1 #include <stdio.h>
     2 #include <string.h>
     3 #include <math.h>
     4 #define maxn 1000000
     5 struct node
     6 {
     7     double x,y,z,r;
     8 }degree[105];
     9 double map[105][105];
    10 
    11 double res(int i,int j)
    12 {
    13     double x,y,z;
    14     x = (degree[i].x-degree[j].x)*(degree[i].x-degree[j].x);
    15     y = (degree[i].y-degree[j].y)*(degree[i].y-degree[j].y);
    16     z = (degree[i].z-degree[j].z)*(degree[i].z-degree[j].z);
    17     double dis;
    18     dis = sqrt(x+y+z);
    19     if(dis > degree[i].r+degree[j].r)
    20     return dis-degree[i].r-degree[j].r;
    21     else
    22     return 0;
    23 }
    24 double prim(int n)
    25 {
    26     int vis[105] = {0};
    27     double dis[105] = {0};
    28 
    29     int i,j,pre;
    30     double min,ans;
    31 
    32     ans = 0;
    33 
    34     vis[1] = 1;
    35     for(i =2;i <= n;i++)
    36     dis[i] = map[1][i];
    37 
    38     for(i = 2;i <= n;i++)
    39     {
    40         min = maxn;
    41         for(j =2;j <= n;j++)
    42         {
    43             if(!vis[j] && min > dis[j])
    44             min = dis[j],pre = j;
    45         }
    46 
    47         vis[pre] = 1;
    48         ans += min;
    49 
    50         for(j = 2;j <= n;j++)
    51         if(!vis[j] && dis[j] > map[pre][j])
    52         dis[j] = map[pre][j];
    53     }
    54     return ans;
    55 }
    56 int main()
    57 {
    58     int n,i,j;
    59     while(scanf("%d",&n)&&n)
    60     {
    61         for(i = 1;i <= n;i++)
    62         scanf("%lf %lf %lf %lf",&degree[i].x,&degree[i].y,&degree[i].z,&degree[i].r);
    63 
    64         for(i = 1;i <= n;i++)
    65         for(j = i+1;j <= n;j++)
    66         map[j][i] = map[i][j] = res(i,j);
    67 
    68         printf("%.3f\n",prim(n));
    69     }
    70 }
    #include <stdio.h>
    #include <math.h>
    #include <stdlib.h>
    #include <string.h>
    struct degree
    {
        double x,y,z,r;
    }point[105];
    
    struct node
    {
        int u,v;
        double w;
    }e[105*105];
    int map[105][105];
    int set[105];
    int count,ncount;
    
    int cmp(const void *a,const void *b)
    {
        return (*(struct node *)a).w>(*(struct node *)b).w ? 1:-1;
    }
    
    
    void init(int n)
    {
        int i;
        for(i = 1;i <= n;i++)
        set[i] = i;
        return;
    }
    
    int find(int x)
    {
        if(x != set[x])
        {
            set[x] = find(set[x]);
        }
        return set[x];
    }
    
    
    void make_edge(int i, int j)
    {
        double dis;
        double x,y,z;
        x = (point[i].x-point[j].x)*(point[i].x-point[j].x);
        y = (point[i].y-point[j].y)*(point[i].y-point[j].y);
        z = (point[i].z-point[j].z)*(point[i].z-point[j].z);
        dis = sqrt(x+y+z);
        if(dis - point[i].r-point[j].r <= 0.000001)
        {
            e[count].u = i,e[count].v = j,e[count].w = 0;
            count++;
            return;
        }
        e[count].u = i,e[count].v = j,e[count].w = dis-point[i].r-point[j].r;
        count++;
        return;
    }
    
    int main()
    {
        int i,j,n;
        double ans;
    
        while(scanf("%d",&n)&&n)
        {
    
            ans = 0;
            init(n);
            for(i = 1;i <= n;i++)
            {
                scanf("%lf %lf %lf %lf",&point[i].x,&point[i].y,&point[i].z,&point[i].r);
            }
            count = 0;
    
            for(i = 1;i <= n;i++)
            {
                for(j = i+1;j <= n;j++)
                make_edge(i,j);
            }
            qsort(e,(n-1)*n/2,sizeof(e[0]),cmp);
    
            for(i = 0;i < (n-1)*n/2;i++)
            {
                int u,v;
                u = find(e[i].u);
                v = find(e[i].v);
                if(u != v)
                {
                    set[u] = v;
                    ans += e[i].w;
                }
            }
            printf("%.3lf\n",ans);
    
        }
    
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/0803yijia/p/2634527.html
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