• HDU1222,HDU1032 水题


    Wolf and Rabbit

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 7646    Accepted Submission(s): 3844


    Problem Description
    There is a hill with n holes around. The holes are signed from 0 to n-1.



    A rabbit must hide in one of the holes. A wolf searches the rabbit in anticlockwise order. The first hole he get into is the one signed with 0. Then he will get into the hole every m holes. For example, m=2 and n=6, the wolf will get into the holes which are signed 0,2,4,0. If the rabbit hides in the hole which signed 1,3 or 5, she will survive. So we call these holes the safe holes.
     

     

    Input
    The input starts with a positive integer P which indicates the number of test cases. Then on the following P lines,each line consists 2 positive integer m and n(0<m,n<2147483648).
     

     

    Output
    For each input m n, if safe holes exist, you should output "YES", else output "NO" in a single line.
     

     

    Sample Input
    2 1 2 2 2
     

     

    Sample Output
    NO YES
     

     

    Author
    weigang Lee
     

     

    Source
    判断n能否整除m(m!=1)。

    The 3n + 1 problem

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 35393    Accepted Submission(s): 12830


    Problem Description
    Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.

    Consider the following algorithm:


        1.      input n

        2.      print n

        3.      if n = 1 then STOP

        4.           if n is odd then n <- 3n + 1

        5.           else n <- n / 2

        6.      GOTO 2


    Given the input 22, the following sequence of numbers will be printed 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1

    It is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1,000,000 (and, in fact, for many more numbers than this.)

    Given an input n, it is possible to determine the number of numbers printed (including the 1). For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.

    For any two numbers i and j you are to determine the maximum cycle length over all numbers between i and j.
     
    Input
    The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 1,000,000 and greater than 0.

    You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j.

    You can assume that no opperation overflows a 32-bit integer.
     
    Output
    For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).
     
    Sample Input
    1 10 100 200 201 210 900 1000
     
    Sample Output
    1 10 20 100 200 125 201 210 89 900 1000 174
     
    Source
    暴力。
    注意:像这种会给出两个数范围的题,前一个数可能比后一个数大!
    代码略。
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  • 原文地址:https://www.cnblogs.com/--ZHIYUAN/p/5954319.html
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