• 给定进制下1-n每一位数的共享(Digit sum)The Preliminary Contest for ICPC Asia Shanghai 2019


    题意:https://nanti.jisuanke.com/t/41422

    对每一位进行找循环节规律就行了。

      1 #define IOS ios_base::sync_with_stdio(0); cin.tie(0);
      2 #include <cstdio>//sprintf islower isupper
      3 #include <cstdlib>//malloc  exit strcat itoa system("cls")
      4 #include <iostream>//pair
      5 #include <fstream>//freopen("C:\Users\13606\Desktop\草稿.txt","r",stdin);
      6 #include <bitset>
      7 //#include <map>
      8 //#include<unordered_map>
      9 #include <vector>
     10 #include <stack>
     11 #include <set>
     12 #include <string.h>//strstr substr
     13 #include <string>
     14 #include <time.h>//srand(((unsigned)time(NULL))); Seed n=rand()%10 - 0~9;
     15 #include <cmath>
     16 #include <deque>
     17 #include <queue>//priority_queue<int, vector<int>, greater<int> > q;//less
     18 #include <vector>//emplace_back
     19 //#include <math.h>
     20 //#include <windows.h>//reverse(a,a+len);// ~ ! ~ ! floor
     21 #include <algorithm>//sort + unique : sz=unique(b+1,b+n+1)-(b+1);+nth_element(first, nth, last, compare)
     22 using namespace std;//next_permutation(a+1,a+1+n);//prev_permutation
     23 #define rint register int
     24 #define fo(a,b,c) for(rint a=b;a<=c;++a)
     25 #define fr(a,b,c) for(rint a=b;a>=c;--a)
     26 #define mem(a,b) memset(a,b,sizeof(a))
     27 #define pr printf
     28 #define sc scanf
     29 #define ls rt<<1
     30 #define rs rt<<1|1
     31 typedef long long ll;
     32 void swapp(int &a,int &b);
     33 double fabss(double a);
     34 int maxx(int a,int b);
     35 int minn(int a,int b);
     36 int Del_bit_1(int n);
     37 int lowbit(int n);
     38 int abss(int a);
     39 const double E=2.718281828;
     40 const double PI=acos(-1.0);
     41 //const ll INF=(1LL<<60);
     42 const int inf=(1<<30);
     43 const double ESP=1e-9;
     44 const int mod=(int)1e9+7;
     45 const int N=(int)1e6+10;
     46 
     47 int ans[12][60];
     48 ll m[20]={0,0,1,3,6,10,15,21,28,36,45};
     49 
     50 int geet(int n,int b)
     51 {
     52     int sum=0;
     53     while(n>0)
     54     {
     55         sum+=n%b;
     56         n/=b;
     57     }
     58     return sum;
     59 }
     60 
     61 ll get(ll n,ll b)
     62 {
     63     ll temp=n;
     64     int l=0;
     65     while(temp>0)
     66     {
     67         temp/=b;
     68         l++;
     69     }
     70     ll sum=0;
     71     ll val[60];
     72     val[l]=1;
     73     n++;
     74     for(int i=l-1;i>=1;--i)
     75         val[i]=val[i+1]*b;
     76     for(int i=1;i<=l;++i)
     77     {
     78         ll LOOP=n/(val[i]*b);
     79         sum+=LOOP*m[b]*val[i];
     80         ll len=n%(val[i]*b);
     81         int start=0;
     82         while(len>=val[i])
     83         {
     84             sum+=start*val[i];
     85             start++;
     86             len-=val[i];
     87         }
     88         sum+=len*start;
     89     }
     90     return sum;
     91 }
     92 
     93 int main()
     94 {
     95     int T,cont=0;
     96     sc("%d",&T);
     97     while(T--)
     98     {
     99         ll n;int b;
    100         sc("%lld%d",&n,&b);
    101         for(int i=2;i<=10;++i)
    102         {
    103             ans[i][1]=1;
    104             for(int j=2;j<=45;++j)
    105                 ans[i][j]=ans[i][j-1]*b;
    106         }
    107 //        for(int i=1;i<=100;++i)
    108     //        pr("%lld
    ",get(i,2));
    109         pr("Case #%d: %lld
    ",++cont,get(n,b));
    110     }
    111     return 0;
    112 }
    113 
    114 /**************************************************************************************/
    115 
    116 int maxx(int a,int b)
    117 {
    118     return a>b?a:b;
    119 }
    120 
    121 void swapp(int &a,int &b)
    122 {
    123     a^=b^=a^=b;
    124 }
    125 
    126 int lowbit(int n)
    127 {
    128     return n&(-n);
    129 }
    130 
    131 int Del_bit_1(int n)
    132 {
    133     return n&(n-1);
    134 }
    135 
    136 int abss(int a)
    137 {
    138     return a>0?a:-a;
    139 }
    140 
    141 double fabss(double a)
    142 {
    143     return a>0?a:-a;
    144 }
    145 
    146 int minn(int a,int b)
    147 {
    148     return a<b?a:b;
    149 }
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  • 原文地址:https://www.cnblogs.com/--HPY-7m/p/11536080.html
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