A+B Coming

Problem Description

Many classmates said to me that A+B is must needs.
If you can’t AC this problem, you would invite me for night meal. ^_^

 

Input

Input may contain multiple test cases. Each case contains A and B in one line.
A, B are hexadecimal number.
Input terminates by EOF.

 

Output

Output A+B in decimal number in one line.

 

Sample Input

1 9

A B

a b

 

Sample Output

10

21

21

 

#include <stdio.h>
#include <string.h>
#include <ctype.h>
#include <math.h>

int decimal(char s[]);

int main(){
    char s1[50];
    char s2[50];
    int number1;
    int number2;
    
    while(scanf("%s%s",s1,s2)!=EOF){
        number1=decimal(s1);
        number2=decimal(s2);
        
        printf("%d
",number1+number2);
        
    }
    
    return 0;
}

int decimal(char s[]){
    int result=0;
    int i;
    int length;
    int temp;
    
    length=strlen(s);
    
    for(i=length-1;i>=0;i--){
        if(isdigit(s[i]))
            temp=s[i]-'0';
            
        else if(s[i]=='A' || s[i]=='a')
            temp=10;
            
        else if(s[i]=='B' || s[i]=='b')
            temp=11;
            
        else if(s[i]=='C' || s[i]=='c')
            temp=12;
            
        else if(s[i]=='D' || s[i]=='d')
            temp=13;
            
        else if(s[i]=='E' || s[i]=='e')
            temp=14;
            
        else if(s[i]=='F' || s[i]=='f')
            temp=15;
            
        result+=temp*pow(16,length-1-i);
    }
    
    return result;
}