• mysql 输出当前月所有日期与对应的星期


    其实可以用存储过程,但想用另一种方法实现:

    首先创建一个辅助表,可以设置CREATE TABLE `t4` (
      `id` int(11) NOT NULL AUTO_INCREMENT,
      `num` int(11) DEFAULT NULL,
      PRIMARY KEY (`id`)
    )
    
    insert into t4(num) select id from xxx limit 31;(偷懒插入31条数据)
    
    alter table t4 drop column num;
    mysql> select * from t4;
    +----+
    | id |
    +----+
    |  1 |
    |  2 |
    |  3 |
    |  4 |
    |  5 |
    |  6 |
    |  7 |
    |  8 |
    |  9 |
    | 10 |
    | 11 |
    | 12 |
    | 13 |
    | 14 |
    | 15 |
    | 16 |
    | 17 |
    | 18 |
    | 19 |
    | 20 |
    | 21 |
    | 22 |
    | 23 |
    | 24 |
    | 25 |
    | 26 |
    | 27 |
    | 28 |
    | 29 |
    | 30 |
    | 31 |
    +----+
    31 rows in set (0.00 sec)
    mysql> set @a=-1; 
    Query OK, 0 rows affected (0.00 sec)
    
    mysql>  select @a:=@a+1,DATE_ADD(DATE_SUB(CURDATE(),INTERVAL DAY(CURDATE())-1 DAY),INTERVAL @a DAY)  AS '日期',DAYNAME(DATE_ADD(DATE_SUB(CURDATE(),INTERVAL DAY(CURDATE())-1 DAY),INTERVAL @a DAY) ) as '星期' from t4 where id<=DAYOFMONTH(last_day(curdate())); 
    +----------+------------+-----------+
    | @a:=@a+1 | 日期       | 星期      |
    +----------+------------+-----------+
    |        0 | 2015-08-01 | Saturday  |
    |        1 | 2015-08-02 | Sunday    |
    |        2 | 2015-08-03 | Monday    |
    |        3 | 2015-08-04 | Tuesday   |
    |        4 | 2015-08-05 | Wednesday |
    |        5 | 2015-08-06 | Thursday  |
    |        6 | 2015-08-07 | Friday    |
    |        7 | 2015-08-08 | Saturday  |
    |        8 | 2015-08-09 | Sunday    |
    |        9 | 2015-08-10 | Monday    |
    |       10 | 2015-08-11 | Tuesday   |
    |       11 | 2015-08-12 | Wednesday |
    |       12 | 2015-08-13 | Thursday  |
    |       13 | 2015-08-14 | Friday    |
    |       14 | 2015-08-15 | Saturday  |
    |       15 | 2015-08-16 | Sunday    |
    |       16 | 2015-08-17 | Monday    |
    |       17 | 2015-08-18 | Tuesday   |
    |       18 | 2015-08-19 | Wednesday |
    |       19 | 2015-08-20 | Thursday  |
    |       20 | 2015-08-21 | Friday    |
    |       21 | 2015-08-22 | Saturday  |
    |       22 | 2015-08-23 | Sunday    |
    |       23 | 2015-08-24 | Monday    |
    |       24 | 2015-08-25 | Tuesday   |
    |       25 | 2015-08-26 | Wednesday |
    |       26 | 2015-08-27 | Thursday  |
    |       27 | 2015-08-28 | Friday    |
    |       28 | 2015-08-29 | Saturday  |
    |       29 | 2015-08-30 | Sunday    |
    |       30 | 2015-08-31 | Monday    |
    +----------+------------+-----------+
    31 rows in set (0.00 sec)
    mysql>  set @a=-1;  
    Query OK, 0 rows affected (0.00 sec)
    
    mysql> select @a:=@a+1,DATE_ADD(DATE_SUB(CURDATE(),INTERVAL DAY(CURDATE())-1 DAY),INTERVAL @a DAY)  AS '日期',WEEKDAY(DATE_ADD(DATE_SUB(CURDATE(),INTERVAL DAY(CURDATE())-1 DAY),INTERVAL @a DAY) )+1 as '星期' from t4 where id<=DAYOFMONTH(last_day(curdate())); 
    +----------+------------+--------+
    | @a:=@a+1 | 日期       | 星期   |
    +----------+------------+--------+
    |        0 | 2015-08-01 |      6 |
    |        1 | 2015-08-02 |      7 |
    |        2 | 2015-08-03 |      1 |
    |        3 | 2015-08-04 |      2 |
    |        4 | 2015-08-05 |      3 |
    |        5 | 2015-08-06 |      4 |
    |        6 | 2015-08-07 |      5 |
    |        7 | 2015-08-08 |      6 |
    |        8 | 2015-08-09 |      7 |
    |        9 | 2015-08-10 |      1 |
    |       10 | 2015-08-11 |      2 |
    |       11 | 2015-08-12 |      3 |
    |       12 | 2015-08-13 |      4 |
    |       13 | 2015-08-14 |      5 |
    |       14 | 2015-08-15 |      6 |
    |       15 | 2015-08-16 |      7 |
    |       16 | 2015-08-17 |      1 |
    |       17 | 2015-08-18 |      2 |
    |       18 | 2015-08-19 |      3 |
    |       19 | 2015-08-20 |      4 |
    |       20 | 2015-08-21 |      5 |
    |       21 | 2015-08-22 |      6 |
    |       22 | 2015-08-23 |      7 |
    |       23 | 2015-08-24 |      1 |
    |       24 | 2015-08-25 |      2 |
    |       25 | 2015-08-26 |      3 |
    |       26 | 2015-08-27 |      4 |
    |       27 | 2015-08-28 |      5 |
    |       28 | 2015-08-29 |      6 |
    |       29 | 2015-08-30 |      7 |
    |       30 | 2015-08-31 |      1 |
    +----------+------------+--------+
    31 rows in set (0.00 sec)
    mysql> set @a=-1;
    Query OK, 0 rows affected (0.00 sec)
    
    mysql> 
    mysql> 
    mysql> select @a:=@a+1,DATE_ADD(DATE_SUB(CURDATE(),INTERVAL DAY(CURDATE())-1 DAY),INTERVAL @a DAY)  AS '日期',DAYOFWEEK(DATE_ADD(DATE_SUB(CURDATE(),INTERVAL DAY(CURDATE())-1 DAY),INTERVAL @a DAY) ) as '星期' from t4 where id<=DAYOFMONTH(last_day(curdate()));
    +----------+------------+--------+
    | @a:=@a+1 | 日期       | 星期   |
    +----------+------------+--------+
    |        0 | 2015-08-01 |      7 |
    |        1 | 2015-08-02 |      1 |
    |        2 | 2015-08-03 |      2 |
    |        3 | 2015-08-04 |      3 |
    |        4 | 2015-08-05 |      4 |
    |        5 | 2015-08-06 |      5 |
    |        6 | 2015-08-07 |      6 |
    |        7 | 2015-08-08 |      7 |
    |        8 | 2015-08-09 |      1 |
    |        9 | 2015-08-10 |      2 |
    |       10 | 2015-08-11 |      3 |
    |       11 | 2015-08-12 |      4 |
    |       12 | 2015-08-13 |      5 |
    |       13 | 2015-08-14 |      6 |
    |       14 | 2015-08-15 |      7 |
    |       15 | 2015-08-16 |      1 |
    |       16 | 2015-08-17 |      2 |
    |       17 | 2015-08-18 |      3 |
    |       18 | 2015-08-19 |      4 |
    |       19 | 2015-08-20 |      5 |
    |       20 | 2015-08-21 |      6 |
    |       21 | 2015-08-22 |      7 |
    |       22 | 2015-08-23 |      1 |
    |       23 | 2015-08-24 |      2 |
    |       24 | 2015-08-25 |      3 |
    |       25 | 2015-08-26 |      4 |
    |       26 | 2015-08-27 |      5 |
    |       27 | 2015-08-28 |      6 |
    |       28 | 2015-08-29 |      7 |
    |       29 | 2015-08-30 |      1 |
    |       30 | 2015-08-31 |      2 |
    +----------+------------+--------+
    31 rows in set (0.00 sec)

    注意:最后一个输出貌似是所有星期都加上1了,感觉不对,其实这是函数的规定来的:

    DAYOFWEEK(date)
    返回日期date的星期索引(1=星期天,2=星期一, ……7=星期六)。这些索引值对应于ODBC标准。
    mysql> select DAYOFWEEK('1998-02-03');

    WEEKDAY(date)
    返回date的星期索引(0=星期一,1=星期二, ……6= 星期天)。
    mysql> select WEEKDAY('1997-10-04 22:23:00');
    -> 5

    这个例子用到的一个技巧是第一个@a:=@a+1来模拟循环记数,伪rownum.

  • 相关阅读:
    轻配置 Vim
    PHP 使用 wkhtmltopdf/image 把HTML页面转换成 PDF/image 文件
    使用 Mailgun 实现 带附件的Email 发送功能
    LinkedIn 第三方登录(JavaScript SDK)
    react学习2
    前端面试题
    react学习
    前端面试-字符串-逆序-间隔
    前端文件上传相关知识
    js原型prototype问题
  • 原文地址:https://www.cnblogs.com/zejin2008/p/4727226.html
Copyright © 2020-2023  润新知