• FWT快速沃尔什变换


    前言

    学多项式怎么能错过(FWT)呢,然而这真是个毒瘤的东西,蒟蒻就只会背公式了(\%>\_<\%)

    或卷积

    [egin{aligned}\ tf(A) = (tf(A_0), tf(A_1) + tf(A_0))\ utf(A) = (utf(A), utf(A_1) - utf(A_0))\ end{aligned}]

    与卷积

    [egin{aligned}\ tf(A) = (tf(A_0) + tf(A_1), tf(A_1))\ utf(A) = (utf(A_0) - utf(A_1), utf(A_1))\ end{aligned}]

    异或卷积

    [egin{aligned}\ tf(A) = (tf(A_0) + tf(A_1), tf(A_0) - tf(A_1))\ utf(A) = (frac{utf(A_0) + utf(A_1)}{2}, frac{utf(A_0) - utf(A_1)}{2})\ end{aligned}]

    Code

    习惯写递归的非递归本来也不会

    #include<bits/stdc++.h>
    typedef int LL;
    inline LL Read(){
    	LL x(0),f(1); char c=getchar();
    	while(c<'0' || c>'9'){
    		if(c=='-') f=-1; c=getchar();
    	}
    	while(c>='0' && c<='9'){
    		x=(x<<3)+(x<<1)+c-'0'; c=getchar();
    	}
    	return x*f;
    }
    const LL mod=998244353,maxn=1<<18,inv2=499122177;
    inline LL Pow(LL base,LL b){
    	LL ret(1);
    	while(b){
    		if(b&1) ret=1ll*ret*base%mod; base=1ll*base*base%mod; b>>=1;
    	}
    	return ret;
    }
    void Solve_or(LL n,LL *a,LL *b,LL *c){
    	n>>=1;
    	if(!n){
    		c[0]=1ll*a[0]*b[0]%mod;
    		return;
    	}
    	for(LL i=0;i<n;++i){
    		a[i+n]=1ll*(a[i+n]+a[i])%mod; b[i+n]=1ll*(b[i+n]+b[i])%mod;
    	}
    	Solve_or(n,a,b,c); Solve_or(n,a+n,b+n,c+n);
    	for(LL i=0;i<n;++i) c[i+n]=(c[i+n]-c[i]+mod)%mod;
    }
    void Solve_and(LL n,LL *a,LL *b,LL *c){
    	n>>=1;
    	if(!n){
    		c[0]=1ll*a[0]*b[0]%mod;
    		return;
    	}
    	for(LL i=0;i<n;++i){
    		a[i]=1ll*(a[i]+a[i+n])%mod; b[i]=1ll*(b[i]+b[i+n])%mod;
    	}
    	Solve_and(n,a,b,c); Solve_and(n,a+n,b+n,c+n);
    	for(LL i=0;i<n;++i) c[i]=1ll*(c[i]-c[i+n]+mod)%mod;
    }
    void Solve_xor(LL n,LL *a,LL *b,LL *c){
    	n>>=1;
    	if(!n){
    		c[0]=1ll*a[0]*b[0]%mod;
    		return;
    	}
    	for(LL i=0;i<n;++i){
    		std::tie(a[i],a[i+n])=std::make_tuple(a[i]+a[i+n],a[i]-a[i+n]+mod);
    		std::tie(b[i],b[i+n])=std::make_tuple(b[i]+b[i+n],b[i]-b[i+n]+mod);
            a[i]%=mod; a[i+n]%=mod; b[i]%=mod; b[i+n]%=mod;
    	}
    	Solve_xor(n,a,b,c); Solve_xor(n,a+n,b+n,c+n);
        for(LL i=0;i<n;++i){
            std::tie(c[i],c[i+n])=std::make_tuple(c[i]+c[i+n],c[i]-c[i+n]+mod);
            c[i]=1ll*c[i]%mod*inv2%mod; c[i+n]=1ll*c[i+n]%mod*inv2%mod;
    	}
    }
    LL n,N;
    LL a[maxn],b[maxn],c[maxn],d[maxn],e[maxn],f[maxn],x[maxn],y[maxn],z[maxn];
    int main(){
    	n=Read();
    	N=1<<n;
    	for(LL i=0;i<N;++i) a[i]=c[i]=e[i]=Read();
    	for(LL i=0;i<N;++i) b[i]=d[i]=f[i]=Read();
    	Solve_or(N,a,b,x);
    	Solve_and(N,c,d,y);
    	Solve_xor(N,e,f,z);
    	for(LL i=0;i<N;++i) printf("%d ",x[i]);printf("
    ");
    	for(LL i=0;i<N;++i) printf("%d ",y[i]);printf("
    ");
    	for(LL i=0;i<N;++i) printf("%d ",z[i]);printf("
    ");
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/y2823774827y/p/10728615.html
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