• python学习笔记 day45 python实现用户权限管理


    1. 需求

    要求使用python实现某个用户登录成功后,查看自己所有的权限;

    思路:创建权限表(都有哪些权限) 用户表(每个用户的用户名密码以及所拥有的权限 用户-权限关系表(存储用户和所拥有权限的对应关系)

    2. 创建表

    -- 创建权限表
    create table authorization(
      id smallint not null auto_increment primary key,
      aid char(10) not null,
      name varchar(40) not null);
    desc authorization;
    show create table authorization;
    
    insert into authorization(aid,name) values("a00001","update_course"),("a00002","view_course"),
       ("a00003","uodate_teachers"),("a00004","view_teachers"),("a00005","update_students"),("a00006","view_teachers")
    
    select * from authorization;
    
    -- 创建用户表(三类用户,管理员,老师,学生)
    create table users(
      id smallint not null auto_increment primary key,
      uid char(10) not null,
      name varchar(40) not null);
    insert into users(uid,name) values("u00001","admin"),("u00002","teachers"),("u00003","students");
    
    select * from users;
    
    
    -- 创建用户信息表(存储用户名,密码,以及对应的用户身份(管理员or 教师 or 学生)
    create table userinfo(
      id smallint not null auto_increment primary key,
      iid char(10) not null,
      name varchar(40) not null,
      password varchar(20) not null,
      uid char(10) not null  -- 跟用户user表的uid关联(表明该用户属于哪一种角色,admin teacher students)
      );
    
    insert into userinfo(iid,name,password,uid) values("i00001","xuanxuan","123","u00001"),
    ("i00002","eva","123","u00002"),("i00003","egon","123","u00002"),("i00004","xixi","123","u00003"),("i00005","haha","123","u00003"),("i00006","hehe","123","u00003");
    
    select * from userinfo;
    
    
    -- 创建关系表(管理员,老师,学生分别拥有什么权限)
    create table relations(
      id smallint not null auto_increment primary key,
      uid char(10) not null,
      aid char(10) not null)
    
    insert into relations(uid,aid) values("u00001","a00001"),("u00001","a00002"),("u00001","a00003"),
    ("u00001","a00004"),("u00001","a00005"),("u00001","a00006"),("u00002","a00001"),("u00002","a00002"),
    ("u00002","a00006"),("u00003","a00002");
    select * from relations;

    运行结果:
           

     3. 代码实现

    import pymysql
    usm=input("username:")
    pwd=input("password:")
    conn=pymysql.connect(host="localhost",user="root",password="*****",database="db666")
    cursor=conn.cursor(cursor=pymysql.cursors.DictCursor)
    sql="select * from userinfo where name=%s and password=%s" # 查看用户名密码是否正确,在userinfo表中就可以登录成功
    cursor.execute(sql,[usm,pwd])  # cursor.execute()返回的是受影响的行数
    result=cursor.fetchone()  # 如果登录成功就会返回该用户的信息,才可以后续查看该用户拥有的权限
    if result:
        print("恭喜您,登录成功")
        sql="select aid,name from authorization as t1 where t1.aid in(select aid from relations where uid=(select uid from userinfo where name=%s and password=%s))"
        cursor.execute(sql,[usm,pwd]) # 利用pymysql模块,执行sql语句,查看所登录用户具有的权限
        result=cursor.fetchall()  # select 查看需要cursor.fetchone()获取查看的信息(但是当增删改操作时需要提交 conn.commit())
        print("你具有的权限为:",result)
    
    else:
        print("登录失败!")
    
    cursor.close()
    conn.close()

     运行结果:

    talk is cheap,show me the code
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  • 原文地址:https://www.cnblogs.com/xuanxuanlove/p/9982013.html
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