弱鸡代码
1 #include <iostream> 2 #include <string> 3 #include <string.h> 4 using namespace std; 5 int main() 6 { 7 std::ios::sync_with_stdio(false); 8 int n,i,j; 9 string str1,str3,str2; 10 cin>>str1; 11 cin>>str2; 12 int len = str1.length(); 13 for( i=0; i<len; i++) 14 { 15 if(str1[i]=='[') 16 { 17 n=0; 18 for( j=i+1;; j++) 19 { 20 if(str1[j]==']') 21 { 22 for(int t=0; t<n-1; t++) 23 str3+=str1[i-1]; 24 break; 25 } 26 else 27 n=n*10+str1[j]-'0'; 28 } 29 i=j; 30 } 31 else 32 str3+=str1[i]; 33 } 34 string::size_type it; 35 it=str3.find(str2); 36 if(it!=string::npos) 37 cout<<"True"<<endl; 38 else 39 cout<<"False"<<endl; 40 return 0; 41 }
大神代码
1 #include <cstdio> 2 #include <cstring> 3 #include <cmath> 4 #include <cstdlib> 5 #include<iostream> 6 using namespace std; 7 #define N 1005 8 typedef long long ll; 9 struct C{ 10 int cnt; 11 char ch; 12 }; 13 C A[N], B[N]; 14 int main() 15 { 16 while (1) 17 { 18 for (int i = 0; i < N; i++) 19 { 20 A[i].cnt = 1; 21 } 22 char temp, t = ' '; 23 int cnt1 = -1, cnt2 = -1; 24 while (scanf("%c", &temp), temp != ' ') 25 { 26 if (t == temp) A[cnt1].cnt++; 27 else if (temp != '[' && t != temp) 28 { 29 cnt1++; 30 } 31 32 if (temp >= 'a' && temp <= 'z') 33 { 34 A[cnt1].ch = temp; 35 t = temp; 36 } 37 if (temp == '[') 38 { 39 int num; 40 scanf("%d%*c", &num); 41 A[cnt1].cnt = num; 42 } 43 } 44 t = ' '; 45 while (scanf("%c", &temp), temp != ' ') 46 { 47 if (temp >= 'a' && temp <= 'z' && temp != t) 48 { 49 B[++cnt2].ch = temp; 50 B[cnt2].cnt = 1; 51 t = temp; 52 } 53 else if (temp == t) 54 { 55 B[cnt2].cnt++; 56 } 57 } 58 /* 59 for(int i=0;i<=cnt1;i++) 60 cout<<A[i].ch<<" "; 61 cout<<endl; 62 for(int i=0;i<=cnt1;i++) 63 cout<<A[i].cnt<<" "; 64 cout<<endl; 65 for(int i=0;i<=cnt2;i++) 66 cout<<B[i].ch<<" "; 67 cout<<endl; 68 for(int i=0;i<=cnt2;i++) 69 cout<<B[i].cnt<<" "; 70 cout<<endl; 71 */ 72 int flag = 0; 73 for (int i = 0; i <= cnt1; i++) 74 { 75 if (A[i].ch == B[0].ch && A[i].cnt >= B[0].cnt) 76 { 77 int flag2 = 1; 78 for (int j = 1; j < cnt2; j++) 79 { 80 if (A[i + j].ch != B[j].ch || A[i + j].cnt != B[j].cnt) 81 { 82 flag2 = 0; 83 break; 84 } 85 } 86 if (flag2) 87 { 88 if (A[i + cnt2].ch == B[cnt2].ch && A[i + cnt2].cnt >= B[cnt2].cnt) 89 { 90 flag = 1; 91 break; 92 } 93 } 94 } 95 } 96 if (cnt1 == -1 && cnt2 == -1) break; 97 if (flag) printf("True "); 98 else printf("False "); 99 } 100 return 0; 101 }
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