• hdu3911——Black And White (线段树区间合并)


    Time limit
    3000 ms
    Memory limit
    32768 kB
    There are a bunch of stones on the beach; Stone color is white or black. Little Sheep has a magic brush, she can change the color of a continuous stone, black to white, white to black. Little Sheep like black very much, so she want to know the longest period of consecutive black stones in a range [i, j].

    Input

     There are multiple cases, the first line of each case is an integer n(1<= n <= 10^5), followed by n integer 1 or 0(1 indicates black stone and 0 indicates white stone), then is an integer M(1<=M<=10^5) followed by M operations formatted as x i j(x = 0 or 1) , x=1 means change the color of stones in range[i,j], and x=0 means ask the longest period of consecutive black stones in range[i,j]

    Output

    When x=0 output a number means the longest length of black stones in range [i,j].

    Sample Input

    4
    1 0 1 0
    5
    0 1 4
    1 2 3
    0 1 4
    1 3 3
    0 4 4

    Sample Output

    1
    2
    0

    题解:

    线段树区间合并裸题。注意要保存最长连续0,方便进行改变时直接01互换就行了。

    代码:

    #include <bits/stdc++.h>
    
    using namespace std;
    
    const int MAXN = 100005;
    int Data[MAXN];
    int Change[MAXN*4];
    
    struct D{
    	int l1;
    	int l0;
    	int r1;
    	int r0;
    	int max1;
    	int max0;
    	int s;
    }Tree[MAXN*4];
    
    void Up(int temp){
    	Tree[temp].l1 = Tree[temp<<1].l1;
    	if(Tree[temp<<1].l1 == Tree[temp<<1].s)Tree[temp].l1 += Tree[temp<<1|1].l1;
    	Tree[temp].r1 = Tree[temp<<1|1].r1;
    	if(Tree[temp<<1|1].r1 == Tree[temp<<1|1].s)Tree[temp].r1 += Tree[temp<<1].r1;
    	Tree[temp].l0 = Tree[temp<<1].l0;
    	if(Tree[temp<<1].l0 == Tree[temp<<1].s)Tree[temp].l0 += Tree[temp<<1|1].l0;
    	Tree[temp].r0 = Tree[temp<<1|1].r0;
    	if(Tree[temp<<1|1].r0 == Tree[temp<<1|1].s)Tree[temp].r0 += Tree[temp<<1].r0;
    	Tree[temp].max1 = max(Tree[temp<<1].max1,Tree[temp<<1|1].max1);
    	Tree[temp].max1 = max(Tree[temp].max1,Tree[temp<<1].r1+Tree[temp<<1|1].l1);
    	Tree[temp].max0 = max(Tree[temp<<1].max0,Tree[temp<<1|1].max0);
    	Tree[temp].max0 = max(Tree[temp].max0,Tree[temp<<1].r0+Tree[temp<<1|1].l0);
    }
    
    void Build(int temp,int left,int right){
    	Tree[temp].s = right-left+1;
    	if(left == right){
    		if(Data[left]){
    			Tree[temp].l1 = Tree[temp].r1 = Tree[temp].max1 = 1;
    			Tree[temp].l0 = Tree[temp].r0 = Tree[temp].max0 = 0;
    		}else {
    			Tree[temp].l1 = Tree[temp].r1 = Tree[temp].max1 = 0;
    			Tree[temp].l0 = Tree[temp].r0 = Tree[temp].max0 = 1;
    		}
    		return ;
    	}
    	int mid = left + (right-left)/2;
    	Build(temp<<1,left,mid);
    	Build(temp<<1|1,mid+1,right);
    	Up(temp);
    }
    
    void PushDown(int temp){
    	if(Change[temp]){
    		Change[temp<<1] ^= 1;
    		Change[temp<<1|1] ^= 1;
    		swap(Tree[temp<<1].l1,Tree[temp<<1].l0);
    		swap(Tree[temp<<1].r1,Tree[temp<<1].r0);
    		swap(Tree[temp<<1].max1,Tree[temp<<1].max0);
    		swap(Tree[temp<<1|1].l1,Tree[temp<<1|1].l0);
    		swap(Tree[temp<<1|1].r1,Tree[temp<<1|1].r0);
    		swap(Tree[temp<<1|1].max1,Tree[temp<<1|1].max0);
    		Change[temp] = 0;
    	}
    }
    
    void Updata(int temp,int left,int right,int ql,int qr){
    	if(ql<=left && qr>=right){
    		Change[temp] ^= 1;
    		swap(Tree[temp].l1,Tree[temp].l0);
    		swap(Tree[temp].r1,Tree[temp].r0);
    		swap(Tree[temp].max1,Tree[temp].max0);
    		return ;
    	}
    	
    	PushDown(temp);
    	
    	int mid = left + (right-left)/2;
    	if(ql<=mid)Updata(temp<<1,left,mid,ql,qr);
    	if(qr>mid)Updata(temp<<1|1,mid+1,right,ql,qr);
    	
    	Up(temp);
    } 
    
    int query(int temp,int left,int right,int ql,int qr){
    	if(ql==left && qr==right)return Tree[temp].max1;
    	
    	PushDown(temp);
    	
    	int mid = left + (right-left)/2;
    	if(qr<=mid)return query(temp<<1,left,mid,ql,qr);
    	else if(ql>mid)return query(temp<<1|1,mid+1,right,ql,qr);
    	else {
    		int a,b,c;
    		a = query(temp<<1,left,mid,ql,mid);
    		b = query(temp<<1|1,mid+1,right,mid+1,qr);
    		c = min(mid-ql+1,Tree[temp<<1].r1) + min(qr-mid,Tree[temp<<1|1].l1);
    		return max(a,max(b,c));
    	}
    }
    
     
    int main(){
    	
    	int N,M;
    	while(scanf("%d",&N)!=EOF){
    		for(int i=1 ; i<=N ; i++){
    			scanf("%d",&Data[i]);
    		}
    		memset(Change,0,sizeof(Change));
    		Build(1,1,N);
    		scanf("%d",&M);
    		int A,B,C;
    		while(M--){
    			scanf("%d %d %d",&A,&B,&C);
    			if(A){
    				Updata(1,1,N,B,C);
    			}else {
    				printf("%d
    ",query(1,1,N,B,C));
    			}
    		}
    	}
    	
    	return 0;
    } 


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  • 原文地址:https://www.cnblogs.com/vocaloid01/p/9514125.html
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