10067 - Playing with Wheels
题目页:https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=1008
从一开始思路就不对,之后才焕然大悟……每次都是这样。
还有,感觉搜索和图遍历有点分不清呢。
在第63行加入
1 if (u == target) 2 return;
可以提速很多,可以从300ms左右降低到100ms以内。
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#include <iostream> #include <queue> #define Dec true #define Inc false int start; // 开始数值 int target; // 目标数值 bool op[4]; // 4 个转盘的操作 int ban_number; // 禁止数的个数 int ban[10001]; // 记录禁止数的数组 struct { int parent; bool used; } buffer[10001]; // 顶点 // 增大数值 void decrease( int current[], int i) { current[i]--; if (current[i] == -1) current[i] = 9; } // 减小数值 void increase( int current[], int i) { current[i]++; if (current[i] == 10) current[i] = 0; } // 广度优先搜索 void bfs() { std::queue< int > q; // 初始化顶点 for ( int i = 0; i < 10000; i++) { buffer[i].parent = -1; buffer[i].used = false ; } // 把禁止数标记为已发现 for ( int i = 0; i < ban_number; i++) { buffer[ban[i]].used = true ; } // 初始化开始节点 buffer[start].used = true ; q.push(start); while (!q.empty()) { int u = q.front(); q.pop(); int depart[4]; int a = u / 1000; int b = (u - a*1000) / 100; int c = (u - a*1000 - b *100) / 10; int d = (u - a*1000 - b *100 - c *10); depart[0] = a; depart[1] = b; depart[2] = c; depart[3] = d; for ( int i = 0; i < 4; i++) { decrease(depart, i); { int x = depart[0] * 1000 + depart[1] * 100 + depart[2] * 10 + depart[3]; if (buffer[x].used == false ) { buffer[x].parent = u; buffer[x].used = true ; q.push(x); } } increase(depart, i); increase(depart, i); { int x = depart[0] * 1000 + depart[1] * 100 + depart[2] * 10 + depart[3]; if (buffer[x].used == false ) { buffer[x].parent = u; buffer[x].used = true ; q.push(x); } } decrease(depart, i); } } } // 读取四个个位数组成一个四位数,并返回这个四位数 int read4() { int a, b, c, d; scanf ( "%d%d%d%d" , &a, &b, &c, &d); return a * 1000 + b *100 + c * 10 + d; } // main int main() { int n; scanf ( "%d" , &n); for ( int i = 0; i < n; i++) { start = read4(); target = read4(); scanf ( "%d" , &ban_number); for ( int j = 0; j < ban_number; j++) { ban[j] = read4(); } bfs(); { int x = target; int steps = 0; while (x != -1 && x != start) { steps++; x = buffer[x].parent; } if (x == start) printf ( "%d
" , steps); else printf ( "-1
" ); } } return 0; } |