Given an array with n objects colored red, white or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white and blue.
Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.
Note: You are not suppose to use the library's sort function for this problem.
Example:
Input: [2,0,2,1,1,0]
Output: [0,0,1,1,2,2]
Follow up:
- A rather straight forward solution is a two-pass algorithm using counting sort.
First, iterate the array counting number of 0's, 1's, and 2's, then overwrite array with total number of 0's, then 1's and followed by 2's. - Could you come up with a one-pass algorithm using only constant space?
0,1,2排序
C++:
1 class Solution { 2 public: 3 void sortColors(vector<int>& nums) { 4 int left = 0 ; 5 int right = nums.size()-1 ; 6 for(int i = 0 ; i <= right ;){ 7 if (nums[i] == 0){ 8 swap(nums[i],nums[left++]) ; 9 i++; 10 }else if (nums[i] == 2){ 11 swap(nums[i],nums[right--]) ; 12 }else{ 13 i++ ; 14 } 15 } 16 } 17 };