今天谈到CPU的计算功率,想到网上流传的Super Pi这个圆周率计算器。
两个Text,一个Timer,一个Command,就可完成Super Pi的工作~
Option Explicit 'Copyright (c) 2015,烟台大学计算机学院 'All right reserved. '作者:邵帅 '文件:工程1.vbp '完成时间:2015年04月03日 '版本号:v1.0 Sub getpi(Optional ByVal nums As Long = 10000) nums = nums 5 Dim max As Long, laptime As Single, result() As String Dim i, j As Long, d As Long, t, g, r, k As Long, f() laptime = Timer max = 10 * nums ReDim f(1 To max) ReDim result(nums) result(0) = vbCrLf For i = 1 To max DoEvents f(i) = 30000 Next For j = max To 1 Step -10 t = 0 DoEvents For i = j To 1 Step -1 DoEvents If j = max Then t = t + f(i) * 1000000 Else t = t + f(i) * 100000 End If r = 8 * i * (2 * i + 1) f(i) = t - Int(t / r) * r d = 2 * i - 1 t = Int(t / r) * d * d Next k = k + 1 result(k) = Format(Int(g + t / 100000) Mod 100000, "00000") If k Mod 20 = 0 Then result(k) = result(k) & vbCrLf If k Mod 200 = 0 Then result(k) = result(k) & "---[" & k * 5 & "]---" & vbCrLf g = t Mod 100000 Next Text1.Text = "3." & Join(result, " ") Open "C:1.txt" For Output As #1 Print #1, Text1.Text Close #1 Timer1.Enabled = False End Sub Private Sub Command1_Click() Timer1.Enabled = True getpi Text2.Text MsgBox "计算完成,共用时" + s1.Caption + "秒。" & vbCrLf & "计算结果将在C:1.txt下显示。" End Sub Private Sub Timer1_Timer() s1.Caption = s1.Caption + 1 End Sub
@ Mayuko