• LeetCode: 520 Detect Capital(easy)


    题目:

    Given a word, you need to judge whether the usage of capitals in it is right or not.

    We define the usage of capitals in a word to be right when one of the following cases holds:

    1. All letters in this word are capitals, like "USA".
    2. All letters in this word are not capitals, like "leetcode".
    3. Only the first letter in this word is capital if it has more than one letter, like "Google".

    Otherwise, we define that this word doesn't use capitals in a right way.

    Example 1:

    Input: "USA"
    Output: True

    Example 2:

    Input: "FlaG"
    Output: False

    Note: The input will be a non-empty word consisting of uppercase and lowercase latin letters.

    代码:

    自己的:

     1 class Solution {
     2 public:
     3     bool detectCapitalUse(string word) {
     4         bool result = 1;
     5         if (word[0] < 'a'){
     6             if (word[1] < 'a'){
     7                 for(int i = 2; i < word.size(); i++){
     8                     if(word[i] > 'Z'){
     9                         result = 0;
    10                         break;
    11                     }
    12                 }
    13             }
    14             else{
    15                 for(int i = 2; i < word.size(); i++){
    16                     if(word[i] < 'a'){
    17                         result = 0;
    18                         break;
    19                     }
    20                 }
    21             }
    22         }
    23         else{
    24             for(auto c : word){
    25                 if (c < 'a'){
    26                     result = 0;
    27                     break;
    28                 }
    29             }
    30         }
    31         return result;  
    32     }
    33 };

    别人的:

     1 class Solution {
     2 public:
     3     bool detectCapitalUse(string word) {
     4         int cnt = 0;
     5         for(int a = 0; a < word.length(); a++ ) {
     6             if('Z' - word[a] >= 0) 
     7                 cnt++;
     8         }
     9         if(cnt == word.length() || cnt == 0 || (cnt == 1 && ('Z' - word[0] >= 0)))
    10             return true;
    11         return false;
    12         
    13     }
    14 };

    对大写字母计数,然后再判断(全是大写、全是小写、首字母大写)

  • 相关阅读:
    Groovy Closure & Action
    Groovy A simple DSL based on groovy
    Groovy 一些小细节
    Android 那些年踩过的坑
    Android Startup
    Android 开发最佳实践
    Android 开发经验-容易忽略的问题
    Android 开发经验-Fragment相关
    AQTime + Delphi
    关于ANSI,unicode与utf-8的区别
  • 原文地址:https://www.cnblogs.com/llxblogs/p/7444406.html
Copyright © 2020-2023  润新知