• lucene学习(二)


    前面我们已经完成了hello world的编写,其实全文检索lucene很简单的,当然主要还是里面自带的一些类我们不熟悉,但是这也没有关系,这些类的方法用起来也很简单,下面是一些教程的截图:

    关于排序的一些简单方法:

     1 public QueryResult search(String queryString, int firstResult, int maxResults) {
     2         try {
     3             // 1,把要搜索的文本解析为 Query
     4             String[] fields = { "name", "content" };  
     5             Map<String, Float> boosts = new HashMap<String, Float>();//(按相关度排序)某个属性的boost的值   (排序)
     6             boosts.put("name", 3f); //认为标题很重要,权值大
     7             // boosts.put("content", 1.0f); 默认为1.0f
     8 
     9             QueryParser queryParser = new MultiFieldQueryParser(fields, analyzer, boosts);
    10             Query query = queryParser.parse(queryString);
    11 
    12             return search(query, firstResult, maxResults);
    13         } catch (Exception e) {
    14             throw new RuntimeException(e);
    15         }
    16     }
    17 
    18     public QueryResult search(Query query, int firstResult, int maxResults) {
    19         IndexSearcher indexSearcher = null;
    20 
    21         try {
    22             // 2,进行查询
    23             indexSearcher = new IndexSearcher(indexPath);
    24             Filter filter = new RangeFilter("size", NumberTools.longToString(200)   //文档document的过滤器
    25                     , NumberTools.longToString(1000), true, true);   //过滤器的效率很低
    26 
    27             // ========== 排序  (默认为相关度排序)
    28             Sort sort = new Sort();
    29             sort.setSort(new SortField("size")); // (自定义排序)默认为升序 这个按size的大小排序
    30             // sort.setSort(new SortField("size", true));  //(自定义排序)按降序排序 这个按size的大小排序
    31             // ==========
    32 
    33             TopDocs topDocs = indexSearcher.search(query, filter, 10000, sort);
    34 
    35             int recordCount = topDocs.totalHits;

    关于lucene的集中查询类:

      1 /**
      2      * 关键词查询TermQuery
      3      * 
      4      * name:room
      5      */
      6     @Test
      7     public void testTermQuery() {
      8         // Term term = new Term("name", "房间");
      9         // Term term = new Term("name", "Room"); // 英文关键词全是小写字符
     10         Term term = new Term("content", "编辑");//属性中的关键字(键值对)
     11         Query query = new TermQuery(term);
     12 
     13         queryAndPrintResult(query);
     14     }
     15 
     16     /**
     17      * 范围查询RangeQuery
     18      * 
     19      * 包含边界:size:[0000000000001e TO 000000000000rs]
     20      * 
     21      * 不包含边界:size:{0000000000001e TO 000000000000rs}
     22      */
     23     @Test
     24     public void testRangeQuery() {
     25         Term lowerTerm = new Term("size", NumberTools.longToString(50));//下边界
     26         Term upperTerm = new Term("size", NumberTools.longToString(100));//上边界
     27         Query query = new RangeQuery(lowerTerm, upperTerm, false);//false表示不包含边界
     28 
     29         queryAndPrintResult(query);
     30     }
     31 
     32     // public static void main(String[] args) {
     33     // System.out.println(Long.MAX_VALUE);
     34     // System.out.println(NumberTools.longToString(1000));
     35     // System.out.println(NumberTools.stringToLong("000000000000rs"));
     36     //
     37     // System.out.println(DateTools.dateToString(new Date(), Resolution.DAY));
     38     // System.out.println(DateTools.dateToString(new Date(), Resolution.MINUTE));
     39     // System.out.println(DateTools.dateToString(new Date(), Resolution.SECOND));
     40     // }
     41 
     42     /**
     43      * 通配符查询WildcardQuery
     44      * 
     45      * '?' 代表一个字符, '*' 代表0个或多个字符
     46      * 
     47      * name:房*
     48      * 
     49      * name:*o*
     50      * 
     51      * name:roo?
     52      */
     53     @Test
     54     public void testWildcardQuery() {
     55         Term term = new Term("content", "luc?");
     56         // Term term = new Term("name", "ro*"); // 前缀查询 PrefixQuery
     57         // Term term = new Term("name", "*o*");
     58         // Term term = new Term("name", "房*");
     59         Query query = new WildcardQuery(term);
     60 
     61         queryAndPrintResult(query);
     62     }
     63 
     64     /**
     65      * 短语查询PhraseQuery
     66      * 
     67      * content:"? 绅士 ? ? 饭店"
     68      * 
     69      * content:"绅士 饭店"~2
     70      */
     71     @Test
     72     public void testPhraseQuery() {
     73         PhraseQuery phraseQuery = new PhraseQuery();
     74         // phraseQuery.add(new Term("content", "绅士"), 1);
     75         // phraseQuery.add(new Term("content", "饭店"), 4);
     76 
     77         phraseQuery.add(new Term("content", "编辑"));
     78         phraseQuery.add(new Term("content", "lucene"));
     79         phraseQuery.setSlop(2);
     80 
     81         queryAndPrintResult(phraseQuery);
     82     }
     83 
     84     /**
     85      * +content:"绅士 饭店"~2 -size:[000000000000dw TO 000000000000rs]
     86      * 
     87      * +content:"绅士 饭店"~2 +size:[000000000000dw TO 000000000000rs]
     88      * 
     89      * content:"绅士 饭店"~2 size:[000000000000dw TO 000000000000rs]
     90      * 
     91      * +content:"绅士 饭店"~2 size:[000000000000dw TO 000000000000rs]
     92      */
     93     @Test
     94     public void testBooleanQuery() {
     95         // 条件1
     96         PhraseQuery query1 = new PhraseQuery();
     97         query1.add(new Term("content", "绅士"));
     98         query1.add(new Term("content", "饭店"));
     99         query1.setSlop(2);
    100 
    101         // 条件2
    102         Term lowerTerm = new Term("size", NumberTools.longToString(500));
    103         Term upperTerm = new Term("size", NumberTools.longToString(1000));
    104         Query query2 = new RangeQuery(lowerTerm, upperTerm, true);
    105 
    106         // 组合
    107         BooleanQuery boolQuery = new BooleanQuery();
    108         boolQuery.add(query1, Occur.MUST);
    109         boolQuery.add(query2, Occur.SHOULD);
    110 
    111         queryAndPrintResult(boolQuery);
    112     }
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  • 原文地址:https://www.cnblogs.com/liangdelin/p/2777474.html
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