Given a string s consists of upper/lower-case alphabets and empty space characters ' '
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World"
,
return 5
.
1 class Solution{ 2 public: 3 int lengthOfLastWord(const char *s){ 4 int count=0,last=0; 5 while(*s) 6 { 7 if(*s++!=' ') 8 { 9 count++; 10 } 11 else if(count>0) 12 { 13 last=count; 14 count=0; 15 } 16 } 17 return (count>0)?count:last; 18 } 19 };