题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=1219
简单题。
收获：
gets()的使用。
AC Me
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 5280 Accepted Submission(s): 2388
Problem Description
Ignatius is doing his homework now. The teacher gives him some articles and asks him to tell how many times each letter appears.
It's really easy, isn't it? So come on and AC ME.
It's really easy, isn't it? So come on and AC ME.
Input
Each article consists of just one line, and all the letters are in lowercase. You just have to count the number of each letter, so do not pay attention to other characters. The length of article is at most 100000. Process to the end of file.
Note: the problem has multi-cases, and you may use "while(gets(buf)){...}" to process to the end of file.
Note: the problem has multi-cases, and you may use "while(gets(buf)){...}" to process to the end of file.
Output
For each article, you have to tell how many times each letter appears. The output format is like "X:N".
Output a blank line after each test case. More details in sample output.
Output a blank line after each test case. More details in sample output.
Sample Input
hello, this is my first acm contest!
work hard for hdu acm.
Sample Output
a:1
b:0
c:2
d:0
e:2
f:1
g:0
h:2
i:3
j:0
k:0
l:2
m:2
n:1
o:2
p:0
q:0
r:1
s:4
t:4
u:0
v:0
w:0
x:0
y:1
z:0
a:2
b:0
c:1
d:2
e:0
f:1
g:0
h:2
i:0
j:0
k:1
l:0
m:1
n:0
o:2
p:0
q:0
r:3
s:0
t:0
u:1
v:0
w:1
x:0
y:0
z:0
Author
Ignatius.L
Source
Recommend
Ignatius.L
#include<stdio.h>
#include<iostream>
#include<string.h>
using namespace std;
int num[26];
char let[27]="abcdefghijklmnopqrstuvwxyz";
char str[20000];
int main()
{
//freopen("test.in","r",stdin);
//freopen("test.out","w",stdout);
int i;
while(gets(str))
{
memset(num,0,sizeof(num));
int len=strlen(str);
//if(len==0)break;
for(int i=0;i<len;i++)
{
if(str[i]>='a'&&str[i]<='z')
{
int t=str[i]-'a';
num[t]++;
}
}
for(int i=0;i<26;i++)
printf("%c:%d\n",let[i],num[i]);
printf("\n");
}
return 0;
}