这道题也比较简单，写三个函数判断三个条件即可.....
但是开始时我按照已经注释掉的提交，居然提示WA，我百思不得其解，后改成上面的判断式就可以了，求高手解答....
1 #include "iostream" 2 3 using namespace std; 4 5 #define Max 21 6 int Function1(char *p,int len); 7 int Function2(char *p,int len); 8 int Function3(char *p,int len); 9 int vowel(char p); 10 int main(void) 11 { 12 char letters[Max]; 13 int len; 14 int condition_1=0,condition_2=0,condition_3=0; 15 while(cin>>letters) 16 { 17 if(!strcmp(letters,"end")) 18 break; 19 len=strlen(letters); 20 condition_1=Function1(letters,len); 21 condition_2=Function2(letters,len); 22 condition_3=Function3(letters,len); 23 if(condition_1&&condition_2&&condition_3) 24 cout<<"<"<<letters<<">"<<" is acceptable."<<endl; 25 else 26 cout<<"<"<<letters<<">"<<" is not acceptable."<<endl; 27 /* if(condition_1==1) 28 { 29 condition_2=Function2(letters,len); 30 if(condition_2==1) 31 { 32 condition_3=Function3(letters,len); 33 if(condition_3==1) 34 cout<<"<"<<letters<<">"<<" is acceptable."<<endl; 35 else cout<<"<"<<letters<<">"<<" is not acceptable."<<endl; 36 } 37 else cout<<"<"<<letters<<">"<<" is not acceptable."<<endl; 38 } 39 else cout<<"<"<<letters<<">"<<" is not acceptable."<<endl;*/ 40 } 41 return 0; 42 } 43 44 45 int Function1(char *p,int len) 46 { 47 for(int i=0;i<len;i++) 48 { 49 if(p[i]=='a'||p[i]=='e'||p[i]=='i'||p[i]=='o'||p[i]=='u') 50 return 1; 51 } 52 return 0; 53 } 54 int Function2(char *p,int len) 55 { 56 for(int i=0;i<len;i++) 57 { 58 if(((i+2)<len)&&(vowel(p[i]))&&(vowel(p[i+1]))&&(vowel(p[i+2]))) 59 return 0; 60 else if(((i+2)<len)&&(!vowel(p[i]))&&(!vowel(p[i+1]))&&(!vowel(p[i+2]))) 61 return 0; 62 } 63 return 1; 64 } 65 int Function3(char *p,int len) 66 { 67 char flag; 68 for(int i=0;i<len;i++) 69 { 70 flag=p[i]; 71 if(((i+1)<len)&&(p[i+1]==flag)&&(flag!='e')&&(flag!='o')) 72 return 0; 73 } 74 return 1; 75 } 76 77 int vowel(char p) 78 { 79 if(p=='a'||p=='e'||p=='i'||p=='o'||p=='u') 80 return 1; 81 else return 0; 82 }