• 297. Serialize and Deserialize Binary Tree


    Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another computer environment.

    Design an algorithm to serialize and deserialize a binary tree. There is no restriction on how your serialization/deserialization algorithm should work. You just need to ensure that a binary tree can be serialized to a string and this string can be deserialized to the original tree structure.

    For example, you may serialize the following tree

        1
       / 
      2   3
         / 
        4   5
    

    as "[1,2,3,null,null,4,5]", just the same as how LeetCode OJ serializes a binary tree. You do not necessarily need to follow this format, so please be creative and come up with different approaches yourself.

    Note: Do not use class member/global/static variables to store states. Your serialize and deserialize algorithms should be stateless.

    Credits:
    Special thanks to @Louis1992 for adding this problem and creating all test cases.

    其实该题目的是设计一个序列化输出,然后反序列得到原值

    你可以选择tree的各种travel, 但是要保正可以得到原来的tree

    我选的是level travel

    /**
     * Definition for a binary tree node.
     * public class TreeNode {
     *     int val;
     *     TreeNode left;
     *     TreeNode right;
     *     TreeNode(int x) { val = x; }
     * }
     */
    public class Codec {
    
        // Encodes a tree to a single string.
        public String serialize(TreeNode root) {
            StringBuilder arr = new StringBuilder();
            arr.append("[");
            if(root == null) return "[]";
            ArrayList<TreeNode> queue = new ArrayList<>();
            queue.add(root);
            arr.append(root.val);
            for (int i = 0; i < queue.size(); i++) {
                TreeNode node = queue.get(i);
                if(node == null) continue;
                queue.add(node.left);
                queue.add(node.right);
            }
            
            while(queue.get(queue.size()-1) == null){   //消去leaf的null
                queue.remove(queue.size()-1);
            }
             
            for(int i = 1 ; i < queue.size(); i++){
                TreeNode node = queue.get(i);
                if(node == null) 
                    arr.append(",").append("null");
                else
                    arr.append(",").append(node.val);
                
            }
            arr.append("]");
            System.out.println(arr.toString());
            return arr.toString();
        }
    
        // Decodes your encoded data to tree.
        public TreeNode deserialize(String data) {
            if(data == null || data.length() == 0 || data.equals("[]")) return null;
            String[] arr = data.substring(1, data.length() - 1).split(",");
            if(arr.length == 0) return null;
            ArrayList<TreeNode> list = new ArrayList<TreeNode>();
            TreeNode root = new TreeNode(Integer.parseInt(arr[0]));
            list.add(root);
            int index = 0;
            boolean isLeftNode = true;
            for(int i = 1 ; i < arr.length ; i++){
                if(!arr[i].equals("null")){
                    TreeNode node = new TreeNode(Integer.parseInt(arr[i]));
                    if(isLeftNode)
                      list.get(index).left = node;
                    else
                      list.get(index).right = node;
                    list.add(node);
                }
                if(!isLeftNode)  index++;
                isLeftNode = !isLeftNode;
            }
            return root;
        }
    }
    
    // Your Codec object will be instantiated and called as such:
    // Codec codec = new Codec();
    // codec.deserialize(codec.serialize(root));
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  • 原文地址:https://www.cnblogs.com/joannacode/p/6104056.html
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