LeetCode 485. Max Consecutive Ones （最长连续1）

Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:

Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
    The maximum number of consecutive 1s is 3.

Note:

• The input array will only contain 0 and 1.
• The length of input array is a positive integer and will not exceed 10,000

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 题目标签：Array

　　题目给了我们一个nums array， 里面只会出现0和1， 让我们找到一个最长连续1的长度。

　　这题很简单，只要维护一个maxCount 就可以了，再设一个count，遇到1的时候，count++；遇到0的时候，把count 和 maxCount 中挑大的继续保存，更新count = 0。

　　注意，最后遍历完，如果最后一段是1的话，还需要维护maxCount一次

Java Solution:

Runtime beats 70.20% 

完成日期：05/10/2017

关键词：Array

关键点：维护一个maxCount

public class Solution 
{
    public int findMaxConsecutiveOnes(int[] nums) 
    {
        int maxCount = 0;
        int count = 0;
        
        for(int i=0; i<nums.length; i++)
        {
            if(nums[i] == 1) // count consecutive ones
                count++;
            else if(nums[i] == 0) // if reach 0, save large count into maxCount
            {
                maxCount = Math.max(maxCount, count);    
                count = 0; // update count to 0
            }
                
        }
        // check the last consecutive ones
        maxCount = Math.max(maxCount, count);
        
        return maxCount;
    }
}

参考资料：N/A

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