• 591. Tag Validator


    Given a string representing a code snippet, you need to implement a tag validator to parse the code and return whether it is valid. A code snippet is valid if all the following rules hold:

    1. The code must be wrapped in a valid closed tag. Otherwise, the code is invalid.
    2. A closed tag (not necessarily valid) has exactly the following format : <TAG_NAME>TAG_CONTENT</TAG_NAME>. Among them, <TAG_NAME> is the start tag, and </TAG_NAME> is the end tag. The TAG_NAME in start and end tags should be the same. A closed tag is valid if and only if the TAG_NAME and TAG_CONTENT are valid.
    3. A valid TAG_NAME only contain upper-case letters, and has length in range [1,9]. Otherwise, the TAG_NAME is invalid.
    4. A valid TAG_CONTENT may contain other valid closed tags, cdata and any characters (see note1) EXCEPT unmatched <, unmatched start and end tag, and unmatched or closed tags with invalid TAG_NAME. Otherwise, the TAG_CONTENT is invalid.
    5. A start tag is unmatched if no end tag exists with the same TAG_NAME, and vice versa. However, you also need to consider the issue of unbalanced when tags are nested.
    6. < is unmatched if you cannot find a subsequent >. And when you find a < or </, all the subsequent characters until the next > should be parsed as TAG_NAME (not necessarily valid).
    7. The cdata has the following format : <![CDATA[CDATA_CONTENT]]>. The range of CDATA_CONTENT is defined as the characters between <![CDATA[ and the first subsequent ]]>.
    8. CDATA_CONTENT may contain any characters. The function of cdata is to forbid the validator to parse CDATA_CONTENT, so even it has some characters that can be parsed as tag (no matter valid or invalid), you should treat it as regular characters.

    Valid Code Examples:

    Input: "<DIV>This is the first line <![CDATA[<div>]]></DIV>"
    Output: True
    Explanation:
    The code is wrapped in a closed tag : <DIV> and </DIV>.
    The TAG_NAME is valid, the TAG_CONTENT consists of some characters and cdata.
    Although CDATA_CONTENT has unmatched start tag with invalid TAG_NAME, it should be considered as plain text, not parsed as tag.
    So TAG_CONTENT is valid, and then the code is valid. Thus return true.
    Input: "<DIV>>> ![cdata[]] <![CDATA[<div>]>]]>]]>>]</DIV>"
    Output: True
    Explanation:
    We first separate the code into : start_tag|tag_content|end_tag.
    start_tag -> "<DIV>"
    end_tag -> "</DIV>"
    tag_content could also be separated into : text1|cdata|text2.
    text1 -> ">> ![cdata[]] "
    cdata -> "<![CDATA[<div>]>]]>", where the CDATA_CONTENT is "<div>]>"
    text2 -> "]]>>]"
    The reason why start_tag is NOT "<DIV>>>" is because of the rule 6. The reason why cdata is NOT "<![CDATA[<div>]>]]>]]>" is because of the rule 7.

    Invalid Code Examples:

    Input: "<A>  <B> </A>   </B>"
    Output: False
    Explanation: Unbalanced. If "<A>" is closed, then "<B>" must be unmatched, and vice versa.
    
    Input: "<DIV>  div tag is not closed  <DIV>"
    Output: False
    
    Input: "<DIV>  unmatched <  </DIV>"
    Output: False
    
    Input: "<DIV> closed tags with invalid tag name  <b>123</b> </DIV>"
    Output: False
    
    Input: "<DIV> unmatched tags with invalid tag name  </1234567890> and <CDATA[[]]>  </DIV>"
    Output: False
    
    Input: "<DIV>  unmatched start tag <B>  and unmatched end tag </C>  </DIV>"
    Output: False

    Note:

    1. For simplicity, you could assume the input code (including the any characters mentioned above) only contain lettersdigits'<','>','/','!','[',']' and ' '.

    Approach #1: Simulate. [Java]

    class Solution {
        public boolean isValid(String code) {
            Stack<String> stack = new Stack<>();
            int i, j;
            for (i = 0; i < code.length(); ) {
                if (i > 0 && stack.empty()) return false;
                if (code.startsWith("<![CDATA[", i)) {
                    j = i + 9;
                    i = code.indexOf("]]>", j);
                    if (i < 0) return false;
                    i += 3;
                } else if (code.startsWith("</", i)) {
                    j = i + 2;
                    i = code.indexOf(">", j);
                    if (i < 0 || i - j > 9 || i == j) return false;
                    for (int k = j; k < i; ++k) 
                        if (!Character.isUpperCase(code.charAt(k))) return false;
                    String substr = code.substring(j, i++);
                    if (stack.empty() || !stack.pop().equals(substr)) return false;
                } else if (code.startsWith("<", i)) {
                    j = i + 1;
                    i = code.indexOf(">", j);
                    if (i < 0 || i - j > 9 || i == j) return false;
                    for (int k = j; k < i; ++k)
                        if (!Character.isUpperCase(code.charAt(k))) return false;
                    String substr = code.substring(j, i++);
                    stack.push(substr);
                } else {
                    i++;
                }
            }
            return stack.empty();
        }
    }
    

      

    Reference:

    https://leetcode.com/problems/tag-validator/discuss/103368/Java-Solution%3A-Use-startsWith-and-indexOf

    永远渴望,大智若愚(stay hungry, stay foolish)
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  • 原文地址:https://www.cnblogs.com/h-hkai/p/10755712.html
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