Given a string representing a code snippet, you need to implement a tag validator to parse the code and return whether it is valid. A code snippet is valid if all the following rules hold:
- The code must be wrapped in a valid closed tag. Otherwise, the code is invalid.
- A closed tag (not necessarily valid) has exactly the following format :
<TAG_NAME>TAG_CONTENT</TAG_NAME>
. Among them,<TAG_NAME>
is the start tag, and</TAG_NAME>
is the end tag. The TAG_NAME in start and end tags should be the same. A closed tag is valid if and only if the TAG_NAME and TAG_CONTENT are valid.- A valid
TAG_NAME
only contain upper-case letters, and has length in range [1,9]. Otherwise, theTAG_NAME
is invalid.- A valid
TAG_CONTENT
may contain other valid closed tags, cdata and any characters (see note1) EXCEPT unmatched<
, unmatched start and end tag, and unmatched or closed tags with invalid TAG_NAME. Otherwise, theTAG_CONTENT
is invalid.- A start tag is unmatched if no end tag exists with the same TAG_NAME, and vice versa. However, you also need to consider the issue of unbalanced when tags are nested.
- A
<
is unmatched if you cannot find a subsequent>
. And when you find a<
or</
, all the subsequent characters until the next>
should be parsed as TAG_NAME (not necessarily valid).- The cdata has the following format :
<![CDATA[CDATA_CONTENT]]>
. The range ofCDATA_CONTENT
is defined as the characters between<![CDATA[
and the first subsequent]]>
.CDATA_CONTENT
may contain any characters. The function of cdata is to forbid the validator to parseCDATA_CONTENT
, so even it has some characters that can be parsed as tag (no matter valid or invalid), you should treat it as regular characters.
Valid Code Examples:
Input: "<DIV>This is the first line <![CDATA[<div>]]></DIV>"
Output: True
Explanation:
The code is wrapped in a closed tag : <DIV> and </DIV>.
The TAG_NAME is valid, the TAG_CONTENT consists of some characters and cdata.
Although CDATA_CONTENT has unmatched start tag with invalid TAG_NAME, it should be considered as plain text, not parsed as tag.
So TAG_CONTENT is valid, and then the code is valid. Thus return true.
Input: "<DIV>>> ![cdata[]] <![CDATA[<div>]>]]>]]>>]</DIV>"
Output: True
Explanation:
We first separate the code into : start_tag|tag_content|end_tag.
start_tag -> "<DIV>"
end_tag -> "</DIV>"
tag_content could also be separated into : text1|cdata|text2.
text1 -> ">> ![cdata[]] "
cdata -> "<![CDATA[<div>]>]]>", where the CDATA_CONTENT is "<div>]>"
text2 -> "]]>>]"
The reason why start_tag is NOT "<DIV>>>" is because of the rule 6. The reason why cdata is NOT "<![CDATA[<div>]>]]>]]>" is because of the rule 7.Invalid Code Examples:
Input: "<A> <B> </A> </B>" Output: False Explanation: Unbalanced. If "<A>" is closed, then "<B>" must be unmatched, and vice versa. Input: "<DIV> div tag is not closed <DIV>" Output: False Input: "<DIV> unmatched < </DIV>" Output: False Input: "<DIV> closed tags with invalid tag name <b>123</b> </DIV>" Output: False Input: "<DIV> unmatched tags with invalid tag name </1234567890> and <CDATA[[]]> </DIV>" Output: False Input: "<DIV> unmatched start tag <B> and unmatched end tag </C> </DIV>" Output: False
Note:
- For simplicity, you could assume the input code (including the any characters mentioned above) only contain
letters
,digits
,'<'
,'>'
,'/'
,'!'
,'['
,']'
and' '
.
Approach #1: Simulate. [Java]
class Solution { public boolean isValid(String code) { Stack<String> stack = new Stack<>(); int i, j; for (i = 0; i < code.length(); ) { if (i > 0 && stack.empty()) return false; if (code.startsWith("<![CDATA[", i)) { j = i + 9; i = code.indexOf("]]>", j); if (i < 0) return false; i += 3; } else if (code.startsWith("</", i)) { j = i + 2; i = code.indexOf(">", j); if (i < 0 || i - j > 9 || i == j) return false; for (int k = j; k < i; ++k) if (!Character.isUpperCase(code.charAt(k))) return false; String substr = code.substring(j, i++); if (stack.empty() || !stack.pop().equals(substr)) return false; } else if (code.startsWith("<", i)) { j = i + 1; i = code.indexOf(">", j); if (i < 0 || i - j > 9 || i == j) return false; for (int k = j; k < i; ++k) if (!Character.isUpperCase(code.charAt(k))) return false; String substr = code.substring(j, i++); stack.push(substr); } else { i++; } } return stack.empty(); } }
Reference: