• SP10628 COT


    Code:

    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #include<string>
    #include<iostream>
    
    
    using namespace std;
    
    void SetIO(string a){
    	string in = a + ".in";
    	freopen(in.c_str(),"r",stdin);
    }
    
    void debug(){
    	cout << 233 << endl;
    }
    
    const int maxn = 100000 + 5;
    
    int n, m;
    
    int val[maxn];
    
    int Sorted[maxn];
    
    inline void Disperse(){
    	sort(Sorted + 1, Sorted + 1 + n);
    	for(int i = 1;i <= n; ++i)
    		val[i] = lower_bound(Sorted + 1, Sorted + 1 + n, val[i]) - Sorted;
    }
    
    int head[maxn << 1], to[maxn << 1], nex[maxn << 1], edges;
    
    inline void add_edge(int u, int v){
    	nex[++edges] = head[u];
    	head[u] = edges;
    	to[edges] = v;
    }
    
    inline void Read(){
    	scanf("%d%d",&n, &m);
    	for(int i = 1;i <= n; ++i){
    		scanf("%d",&val[i]), Sorted[i] = val[i];
    	}
    
    	for(int i = 1;i < n; ++i){
    		int a, b;
    		scanf("%d%d",&a,&b);
    		add_edge(a,b);
    		add_edge(b,a);
    	}
    }
    
    const int Tree_const = 50; 
    
    int root[maxn];
    
    struct Chair_Tree{
    	int cnt_node;
    
    	int sumv[maxn * Tree_const], lson[maxn * Tree_const], rson[maxn * Tree_const];
    
    	void build(int l, int r, int &o){
    		if(l > r) return ;
    		o = ++ cnt_node;
    		if(l == r) return ;
    		int mid = (l + r) >> 1;
    		build(l, mid, lson[o]);
    		build(mid + 1, r, rson[o]);
    	}
    
    	int insert(int l, int r, int o, int pos){
    		int oo = ++cnt_node;
    		lson[oo] = lson[o];
    		rson[oo] = rson[o];
    		sumv[oo] = sumv[o] + 1;
    
    		if(l == r) return oo;
    
    		int mid = (l + r) >> 1;
    		if(pos <= mid) lson[oo] = insert(l, mid, lson[o], pos);
    		else rson[oo] = insert(mid + 1, r, rson[o], pos);
    		return oo;
    	}
    
    	int query(int l, int r, int u, int v, int lca, int lca_fa, int k){
    		if(l == r) return l;
    		int lsum = sumv[lson[u]] + sumv[lson[v]] - sumv[lson[lca]] - sumv[lson[lca_fa]];
    		int mid = (l + r) >> 1;
    		if(k <= lsum) return query(l, mid, lson[u], lson[v], lson[lca], lson[lca_fa], k);
    		else return query(mid + 1, r, rson[u], rson[v], rson[lca], rson[lca_fa], k - lsum);
    	}
    
    }Tree;
    
    const int logn = 20;
    
    int f[23][maxn];
    
    int dep[maxn];
    
    void dfs(int u, int fa, int depth){
    
    	root[u] = Tree.insert(1, n, root[fa], val[u]);
    	dep[u] = depth;
    	f[0][u] = fa;
    
    	for(int v = head[u]; v ; v = nex[v]){
    		if(to[v] == fa) continue;
    		dfs(to[v], u, depth + 1);
    	}
    }
    
    inline void get_ancester(){
    	for(int i = 1;i <= logn; ++i){
    		for(int j = 1;j <= n; ++j)
    			f[i][j] = f[i - 1][f[i - 1][j]];
    	}
    }
    
    inline int get_lca(int a, int b){
    	if(dep[a] > dep[b]) swap(a,b);
    	if(dep[a] != dep[b]){
    	    for(int i = logn;i >= 0;--i){
    		    if(dep[f[i][b]] >= dep[a]) b = f[i][b];
    	    }
    	}
    	if(a == b) return a;
    	for(int i = logn;i>=0;--i)
    		if(f[i][a] != f[i][b]) a = f[i][a], b = f[i][b];
    	return f[0][a];
    }
    
    inline void Build(){
    	Tree.build(1, n, root[0]);
    	dfs(1, 0, 1);
    	get_ancester();
    }
    
    inline void Init(){
    	Read();
    	Disperse();
    	Build();
    }
    
    inline void Work(){
    
    	int lastans = 0;
    
    	while(m--){
    		int u, v, k;
    		scanf("%d%d%d",&u, &v, &k);
    	//	u ^= lastans;
    
    		int lca = get_lca(u, v);
    
    		lastans = Tree.query(1, n, root[u], root[v], root[lca], root[f[0][lca]], k);
    		lastans = Sorted[lastans];
    
    		printf("%d
    ", lastans);
    	}
    }
    
    int main(){
    	SetIO("input");
    	Init();
    	Work();
    	return 0;
    }
    

      

  • 相关阅读:
    BZOJ 4236~4247 题解
    OCUI界面设计:滚动视图与分页控件初探
    大数乘法
    Effective C++ 11-17
    [Matlab+C/C++] 读写二进制文件
    Java 反射 方法调用
    如何使用LaTeX让自己不乱?
    LaTeX 相对于 Word 有什么优势?
    你在发表理科学术文章过程中有哪些经验值得借鉴?
    破译手势在对话中的意义
  • 原文地址:https://www.cnblogs.com/guangheli/p/9845066.html
Copyright © 2020-2023  润新知