5C

Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".

Input

each test case contains two numbers A and B. 

Output

for each case, if A is equal to B, you should print "YES", or print "NO".

Sample Input

1 2
2 2
3 3
4 3

Sample Output

NO
YES
YES
NO

// too young

#include<stdio.h>
int main()
{
    int a, b;
    while(scanf("%d %d", &a, &b)!=EOF)
    {
        if(a==b) printf("YES
");
        else printf("NO
");
    }
    return 0;
}

// double只能表示15或16位有效数字，而这道题数字可能会十分长
// 传送门：准确详解：C/C++ float、double数据类型的表示范围及精度

#include<stdio.h>
#include<stdlib.h>
int main()
{
    double a,b;
    char num1[1000000], num2[1000000];
    while(scanf("%s %s", num1, num2)!=EOF)
    {
        a=atof(num1); b=atof(num2);
        if(a==b) printf("YES
");
        else printf("NO
");
    }
    return 0;
}

// 小数点后无意义的零要删去

#include<stdio.h>
#include<string.h>
char a[1000000], b[1000000];
void process(char *num)
{
    int len=strlen(num);
    if(strstr(num,".")!=NULL)
    {
        while(num[--len]=='0');
        if(num[len]=='.')
            num[len]='';
    }
}
int main()
{
    while(scanf(" %s %s", a, b)!=EOF)
    {
        process(a); process(b);
        if(strcmp(a,b)) printf("NO
");
        else printf("YES
");
    }
    return 0;
}

// 

#include<stdio.h>
#include<string.h>
char a[1000000], b[1000000];
void process(char *num)
{
    int len=strlen(num);
    if(strstr(num,".")!=NULL)
    {
        while(num[--len]=='0');
        if(num[len]=='.')
            len--;
        num[++len]='';
    }
}
int main()
{
    while(scanf(" %s %s", a, b)!=EOF)
    {
        process(a); process(b);
        if(strcmp(a,b)) printf("NO
");
        else printf("YES
");
    }
    return 0;
}

// 判断两数是否相等还可用strcmp
// char *strstr(char *str1, char *str2); 寻找str2在str1中第一次出现的位置，返回位置指针