题目描述:
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
直接贴答案了。
solution:
struct ListNode { int val; ListNode *next; ListNode(int x) : val(x), next(NULL) {} }; ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) { if(l1 == NULL) return l2; if(l2 == NULL) return l1; ListNode *head = new ListNode(0); ListNode *p = head; while (l1 != NULL && l2 != NULL) { if (l1->val < l2->val) { p->next = l1; l1 = l1->next; } else { p->next = l2; l2 = l2->next; } p = p->next; } p->next = l1 ? l1 : l2; return head->next; }
递归解法:
ListNode* mergeTwoLists(ListNode *l1, ListNode *l2) { if(l1 == NULL) return l2; if(l2 == NULL) return l1; if (l1->val < l2->val) { l1->next = mergeTwoLists(l1->next, l2); return l1; } else { l2->next = mergeTwoLists(l2->next, l1); return l2; } }