• ByteUnit


    JDK里面有TimeUnit,看spark源码有个ByteUnit。这个类还是挺不错的。

    public enum ByteUnit {
        BYTE (1),
        KiB (1024L),
        MiB ((long) Math.pow(1024L, 2L)),
        GiB ((long) Math.pow(1024L, 3L)),
        TiB ((long) Math.pow(1024L, 4L)),
        PiB ((long) Math.pow(1024L, 5L));
    
        private ByteUnit(long multiplier) {
            this.multiplier = multiplier;
        }
    
        // Interpret the provided number (d) with suffix (u) as this unit type.
        // E.g. KiB.interpret(1, MiB) interprets 1MiB as its KiB representation = 1024k
        public long convertFrom(long d, ByteUnit u) {
            return u.convertTo(d, this);
        }
    
        // Convert the provided number (d) interpreted as this unit type to unit type (u).
        public long convertTo(long d, ByteUnit u) {
            if (multiplier > u.multiplier) {
                long ratio = multiplier / u.multiplier;
                if (Long.MAX_VALUE / ratio < d) {
                    throw new IllegalArgumentException("Conversion of " + d + " exceeds Long.MAX_VALUE in "
                            + name() + ". Try a larger unit (e.g. MiB instead of KiB)");
                }
                return d * ratio;
            } else {
                // Perform operations in this order to avoid potential overflow
                // when computing d * multiplier
                return d / (u.multiplier / multiplier);
            }
        }
    
        public double toBytes(long d) {
            if (d < 0) {
                throw new IllegalArgumentException("Negative size value. Size must be positive: " + d);
            }
            return d * multiplier;
        }
    
        public long toKiB(long d) { return convertTo(d, KiB); }
        public long toMiB(long d) { return convertTo(d, MiB); }
        public long toGiB(long d) { return convertTo(d, GiB); }
        public long toTiB(long d) { return convertTo(d, TiB); }
        public long toPiB(long d) { return convertTo(d, PiB); }
    
        private final long multiplier;
    }
  • 相关阅读:
    平衡数问题
    重复值判断练习题
    小范围排序
    堆排序
    基数排序
    计数排序
    希尔排序
    快速排序
    Effective C++笔记:实现
    Effective C++笔记:设计与声明
  • 原文地址:https://www.cnblogs.com/gaoxing/p/4941830.html
Copyright © 2020-2023  润新知