A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than or equal to the node's key.
- Both the left and right subtrees must also be binary search trees.
A Complete Binary Tree (CBT) is a tree that is completely filled, with the possible exception of the bottom level, which is filled from left to right.
Now given a sequence of distinct non-negative integer keys, a unique BST can be constructed if it is required that the tree must also be a CBT. You are supposed to output the level order traversal sequence of this BST.
Input Specification:
Each input file contains one test case. For each case, the first line contains a positive integer N (≤). Then N distinct non-negative integer keys are given in the next line. All the numbers in a line are separated by a space and are no greater than 2000.
Output Specification:
For each test case, print in one line the level order traversal sequence of the corresponding complete binary search tree. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line.
Sample Input:
10
1 2 3 4 5 6 7 8 9 0
Sample Output:
6 3 8 1 5 7 9 0 2 4
#include<bits/stdc++.h> using namespace std; const int maxn=1010; #define inf 0x3fffffff int number[maxn],cbt[maxn]; int iindex=0;//注意:定义为index会报错,因为头文件中包含该词语 int n; void inorder(int root){//中序遍历,假设cbt中已经存入完全二叉树的值,那么它的中序遍历就是number的值 if(root>n){ return ; } inorder(root*2); cbt[root]=number[iindex++]; inorder(root*2+1); } int main(){ scanf("%d",&n); for(int i=0;i<n;i++){ scanf("%d",&number[i]); } sort(number,number+n); inorder(1); for(int i=1;i<=n;i++){ if(i<=n-1) printf("%d ",cbt[i]); else printf("%d ",cbt[i]); } return 0; }