• 1064 Complete Binary Search Tree (30 分)


    A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:

    • The left subtree of a node contains only nodes with keys less than the node's key.
    • The right subtree of a node contains only nodes with keys greater than or equal to the node's key.
    • Both the left and right subtrees must also be binary search trees.

    A Complete Binary Tree (CBT) is a tree that is completely filled, with the possible exception of the bottom level, which is filled from left to right.

    Now given a sequence of distinct non-negative integer keys, a unique BST can be constructed if it is required that the tree must also be a CBT. You are supposed to output the level order traversal sequence of this BST.

    Input Specification:

    Each input file contains one test case. For each case, the first line contains a positive integer N (≤). Then N distinct non-negative integer keys are given in the next line. All the numbers in a line are separated by a space and are no greater than 2000.

    Output Specification:

    For each test case, print in one line the level order traversal sequence of the corresponding complete binary search tree. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line.

    Sample Input:

    10
    1 2 3 4 5 6 7 8 9 0
     

    Sample Output:

    6 3 8 1 5 7 9 0 2 4
     
    #include<bits/stdc++.h>
    using namespace std;
    const int maxn=1010;
    #define  inf  0x3fffffff
    int number[maxn],cbt[maxn];
    int iindex=0;//注意:定义为index会报错,因为头文件中包含该词语
    int n;
    void inorder(int root){//中序遍历,假设cbt中已经存入完全二叉树的值,那么它的中序遍历就是number的值
        if(root>n){
            return ;
        }
        inorder(root*2);
        cbt[root]=number[iindex++];
        inorder(root*2+1);
    }
    int main(){
        scanf("%d",&n);
        for(int i=0;i<n;i++){
            scanf("%d",&number[i]);
        }
        sort(number,number+n);
        inorder(1);
        for(int i=1;i<=n;i++){
            if(i<=n-1)
            printf("%d ",cbt[i]);
            else
            printf("%d
    ",cbt[i]);
        }
        return 0;
    }
     
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  • 原文地址:https://www.cnblogs.com/dreamzj/p/14442222.html
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