Oracle “CONNECT BY”是层次查询子句,一般用于树状或者层次结果集的查询。其语法是:
[ START
WITH
condition ]
CONNECT
BY
[ NOCYCLE ] condition
说明:
1. START WITH:告诉系统以哪个节点作为根结点开始查找并构造结果集,该节点即为返回记录中的最高节点。
2. 当分层查询中存在上下层互为父子节点的情况时,会返回ORA-01436错误。此时,需要在connect by后面加上NOCYCLE关键字。同时,可用connect_by_iscycle伪列定位出存在互为父子循环的具体节点。 connect_by_iscycle必须要跟关键字NOCYCLE结合起来使用
[例1]
创建一个部门表,这个表有三个字段,分别对应部门ID,部门名称,以及上级部门ID
DEPID DEPNAME UPPERDEPID ----------- -------------------------------------------------------------------------------- ----------- 0 General Deparment 1 Development 0 2 QA 0 3 Server Development 1 4 Client Development 1 5 TA 2 6 Porject QA 2
现在我要根据“CONNECT BY”来实现树状查询结果
SQL> SELECT RPAD( ' ', 2*(LEVEL-1), '-' ) || DEPNAME "DEPNAME", CONNECT_BY_ROOT DEPNAME "ROOT", CONNECT_BY_ISLEAF "ISLEAF", LEVEL , SYS_CONNECT_BY_PATH(DEPNAME, '/') "PATH" FROM DEP START WITH UPPERDEPID IS NULL CONNECT BY PRIOR DEPID = UPPERDEPID; DEPNAME ROOT ISLEAF LEVEL PATH ------------------------------ ------------------- ---------- ---------- -------------------------------------------------------------------------------- General Deparment General Deparment 0 1 /General Deparment -Development General Deparment 0 2 /General Deparment/Development ---Server Development General Deparment 1 3 /General Deparment/Development/Server Development ---Client Development General Deparment 1 3 /General Deparment/Development/Client Development -QA General Deparment 0 2 /General Deparment/QA ---TA General Deparment 1 3 /General Deparment/QA/TA ---Porject QA General Deparment 1 3 /General Deparment/QA/Porject QA
说明:
1. CONNECT_BY_ROOT 返回当前节点的最顶端节点
2. CONNECT_BY_ISLEAF 判断是否为叶子节点,如果这个节点下面有子节点,则不为叶子节点
3. LEVEL 伪列表示节点深度
4. SYS_CONNECT_BY_PATH函数显示详细路径,并用“/”分隔
例2:
1.根据树形结构查子类
select * from xxxx where levelpermission = 0 and validflag = 1 start with id = '20130718091552GRP60000001' connect by prior id=PARENTID
2. 根据属性结构查询父类
select * from xxxx where levelpermission = 0 and validflag = 1 start with id = '40288181455dbe1701455ee92b9d001d' connect by prior PARENTID=id
例三:
通过CONNECT BY生成序列
SQL> SELECT ROWNUM FROM DUAL CONNECT BY ROWNUM <= 5; ROWNUM ---------- 1 2 3 4 5
http://www.cnblogs.com/lettoo/archive/2010/08/03/1791239.html