c++ string 与 char 互转
很简单如下
char bts[5] = {'A','B','C','D','E'}; printf("%s ",bts); //char to string std::string strBts = bts; std::cout << strBts << std::endl; //string to char char *theBts = (char *)strBts.c_str(); printf("%s ",theBts);
c++ base64 工具
// // base64.h // CPPWork // from http://stackoverflow.com/questions/180947/base64-decode-snippet-in-c // Created by cocoa on 16/8/5. // Copyright © 2016年 cc. All rights reserved. // #ifndef base64_h #define base64_h #include <string> std::string base64_encode(unsigned char const* bytes_to_encode, unsigned int in_len); std::string base64_decode(std::string const& encoded_string); #endif /* base64_h */
// // base64.cpp // CPPWork // // Created by cocoa on 16/8/5. // Copyright © 2016年 cc. All rights reserved. // #include "base64.h" #include <iostream> static const std::string base64_chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ" "abcdefghijklmnopqrstuvwxyz" "0123456789+/"; static inline bool is_base64(unsigned char c) { return (isalnum(c) || (c == '+') || (c == '/')); } std::string base64_encode(unsigned char const* bytes_to_encode, unsigned int in_len) { std::string ret; int i = 0; int j = 0; unsigned char char_array_3[3]; unsigned char char_array_4[4]; while (in_len--) { char_array_3[i++] = *(bytes_to_encode++); if (i == 3) { char_array_4[0] = (char_array_3[0] & 0xfc) >> 2; char_array_4[1] = ((char_array_3[0] & 0x03) << 4) + ((char_array_3[1] & 0xf0) >> 4); char_array_4[2] = ((char_array_3[1] & 0x0f) << 2) + ((char_array_3[2] & 0xc0) >> 6); char_array_4[3] = char_array_3[2] & 0x3f; for(i = 0; (i <4) ; i++) ret += base64_chars[char_array_4[i]]; i = 0; } } if (i) { for(j = i; j < 3; j++) char_array_3[j] = '