面试题32 - I. 从上到下打印二叉树
代码:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> levelOrder(TreeNode* root) {
vector<int> res;
if (!root) return res;
queue<TreeNode*> q;
q.push(root);
while (!q.empty()) {
TreeNode* cur = q.front();
res.push_back(cur->val);
q.pop();
if (cur->left != nullptr) q.push(cur->left);
if (cur->right != nullptr) q.push(cur->right);
}
return res;
}
};
面试题32 - II. 从上到下打印二叉树 II
代码:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<vector<int>> levelOrder(TreeNode* root) {
vector<vector<int>> res;
if (!root) return res;
queue<TreeNode*> q;
q.push(root);
vector<int> tmp;
while (!q.empty()) {
int s = q.size();
tmp.clear();
for (int i = 0; i < s; i++) {
TreeNode* cur = q.front();
tmp.push_back(cur->val);
q.pop();
if (cur->left != nullptr) q.push(cur->left);
if (cur->right != nullptr) q.push(cur->right);
}
if (!tmp.empty()) res.push_back(tmp);
}
return res;
}
};
面试题32 - III. 从上到下打印二叉树 III
代码:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<vector<int>> levelOrder(TreeNode* root) {
vector<vector<int>> res;
if (!root) return res;
queue<TreeNode*> q;
q.push(root);
q.push(nullptr);
vector<int> level;
bool zigzag = false;
while (q.size()) {
auto t = q.front();
q.pop();
if (!t) {
if (level.empty()) break;
if (zigzag) reverse(level.begin(), level.end());
res.push_back(level);
level.clear();
q.push(nullptr);
zigzag = !zigzag;
continue;
}
level.push_back(t->val);
if (t->left) q.push(t->left);
if (t->right) q.push(t->right);
}
return res;
}
};