c语言---枚举

当一个变量只有几种可能的取值时，则可以定义为枚举类型的变量。

一：枚举类型的输出

#include<stdio.h>

enum month {ill,Jan,Feb,Mar,Apr,May,Jun
};
int main(){
    int i;
    enum month m;
    for(i=0;i<6;i++){
    printf("
please input month name:");
    scanf("%d",&m);
    switch(m){
        case ill:
            printf("illegal month
");
            break;
        case Jan:
            printf("January
");
            break;
        case Feb:
            printf("February
");
            break;
        case Mar:
            printf("March
");
            break;
        case Apr:
            printf("April
");
            break;
        case May:
            printf("May");
            break;
        case Jun:
            printf("June
");
            break;
    }    
}
    
    return 0;
}

二：枚举元素的输出

#include<stdio.h>
int main(){
    enum language{Basic,Fortran,C
    };
    enum language used;
    used=Fortran;
    if(used==Basic){
        printf("It is Basic
");
    }
    else if(used==Fortran){
        printf("It is Fortran
");
    }
    else{
        printf("It is C
");
    }
    printf("used=%d
",used);
    printf("Basic=%d
Fortran=%d
C=%d",Basic,Fortran,C);
    return 0;
}

实例：假定周一至周五每小时工资3元，每周六工资每小时4元，每周日工资每小时5元，输入一周每天的工作时数，计算周工资数。

#include<stdio.h>

int main(){
    enum weekday{sun,mon,tue,wed,thu,fri,sat
};
    enum weekday workday;
    int pay,hour,total;
    total=0;
    printf("请输入周日到周六的工作时间：
");
//进行强制转换 (weekday)(workday+1)
    for(workday=sun;workday<=sat;workday=(weekday)(workday+1)){
        scanf("%d",&hour);
        switch(workday){
            case sun:
                pay = hour*5;break;
            case sat:
                pay = hour*4;break;
            default:
                pay = hour*3;break;    
        }
        total+=pay;
    }
    
    
    printf("total pay is %d",total);
    return 0;
}