• BUUCTF-RE-SimpleRev


    拿到题目,是64位ELF

    IDA查看

     点进去

    unsigned __int64 Decry()
    {
      char v1; // [rsp+Fh] [rbp-51h]
      int v2; // [rsp+10h] [rbp-50h]
      int v3; // [rsp+14h] [rbp-4Ch]
      int i; // [rsp+18h] [rbp-48h]
      int v5; // [rsp+1Ch] [rbp-44h]
      char src[8]; // [rsp+20h] [rbp-40h]
      __int64 v7; // [rsp+28h] [rbp-38h]
      int v8; // [rsp+30h] [rbp-30h]
      __int64 v9; // [rsp+40h] [rbp-20h]
      __int64 v10; // [rsp+48h] [rbp-18h]
      int v11; // [rsp+50h] [rbp-10h]
      unsigned __int64 v12; // [rsp+58h] [rbp-8h]
    
      v12 = __readfsqword(0x28u);
      *(_QWORD *)src = 'SLCDN';
      v7 = 0LL;
      v8 = 0;
      v9 = 'wodah';
      v10 = 0LL;
      v11 = 0;
      text = join(key3, (const char *)&v9);
      strcpy(key, key1);
      strcat(key, src);
      v2 = 0;
      v3 = 0;
      getchar();
      v5 = strlen(key);
      for ( i = 0; i < v5; ++i )
      {
        if ( key[v3 % v5] > 64 && key[v3 % v5] <= 90 )
          key[i] = key[v3 % v5] + 32;
        ++v3;
      }
      printf("Please input your flag:", src);
      while ( 1 )
      {
        v1 = getchar();
        if ( v1 == '
    ' )
          break;
        if ( v1 == ' ' )
        {
          ++v2;
        }
        else
        {
          if ( v1 <= 96 || v1 > 122 )
          {
            if ( v1 > 64 && v1 <= 90 )
              str2[v2] = (v1 - 39 - key[v3++ % v5] + 97) % 26 + 97;
          }
          else
          {
            str2[v2] = (v1 - 39 - key[v3++ % v5] + 97) % 26 + 97;
          }
          if ( !(v3 % v5) )
            putchar(32);
          ++v2;
        }
      }
      if ( !strcmp(text, str2) )
        puts("Congratulation!
    ");
      else
        puts("Try again!
    ");
      return __readfsqword(0x28u) ^ v12;
    }

    可以看到text是最终比较的结果,经过join处理后,其结果为killshadow

    join:

     key经过拼接,为ADSFKNDCLS后经处理,变为小写

    然后写脚本

    text = 'killshadow'
    key = 'adsfkndcls'
    key_ = ''
    v3=0
    for i in range(len(key)):
            flag = ord(key[v3%len(key)])
            if flag > 64 and flag <=90:
                    key_ += chr(ord(key[v3%len(key)])+32)
            v3=v3+1
    ans = ''
    for i in range(len(key)):
            for j in range(0,15):
                    tmp=chr(ord(text[i]) - 97 + 26*j - 97 + ord(key [v3%len(key)]) + 39)
                    if ord(tmp)>64 and ord(tmp) <91:
                            ans+=tmp
                            break
            v3=v3+1
    print ans

    得出flag为KLDQCUDFZO

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  • 原文地址:https://www.cnblogs.com/basstorm/p/12616253.html
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