• Happy Number


    Write an algorithm to determine if a number is "happy".

    A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.

    Example: 19 is a happy number

    • 12 + 92 = 82
    • 82 + 22 = 68
    • 62 + 82 = 100
    • 12 + 02 + 02 = 1

    分析:如果算得数字为1,则为Happy Number;如果进入无限循环,则不是Happy Number。

    采用set进行存储,每进行一次平方求和(假设结果为s),对set内的数字进行判断:如果set中已经出现s,则表示会进入循环,返回false;否则,将s加入set。

    运行时间:7ms

     1 class Solution {
     2 public:
     3     bool isHappy(int n){
     4         set<int> s;
     5         int recur = compute(n);
     6         while(true){
     7             if(recur == 1) return true;
     8             else{
     9                 if(s.find(recur) != s.end()) return false;
    10                 else{
    11                     s.insert(recur);
    12                     recur = compute(recur);
    13                 }
    14             }
    15         }
    16     }
    17     int compute(int n){
    18         int sum = 0;
    19         while(n){
    20             int temp = n % 10;
    21             sum += temp * temp;
    22             n /= 10;
    23         }
    24         return sum;
    25     }
    26 };

    Runtime: 4ms

     1 class Solution {
     2 private:
     3     int compute(int n){
     4         if(n == 0) return n;
     5         
     6         int result = 0;
     7         while(n){
     8             int temp = n % 10;
     9             result += temp * temp;
    10             n /= 10;
    11         }
    12         return result;
    13     }
    14 public:
    15     bool isHappy(int n) {
    16         unordered_map<int, int> m;
    17         
    18         while(n != 1){
    19             n = compute(n);
    20             if(m.find(n) != m.end())
    21                 return false;
    22             else
    23                 m[n] = n;
    24         }
    25         return true;
    26     }
    27 };
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  • 原文地址:https://www.cnblogs.com/amazingzoe/p/4489798.html
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