Write an algorithm to determine if a number is "happy".
A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.
Example: 19 is a happy number
- 12 + 92 = 82
- 82 + 22 = 68
- 62 + 82 = 100
- 12 + 02 + 02 = 1
分析:如果算得数字为1,则为Happy Number;如果进入无限循环,则不是Happy Number。
采用set进行存储,每进行一次平方求和(假设结果为s),对set内的数字进行判断:如果set中已经出现s,则表示会进入循环,返回false;否则,将s加入set。
运行时间:7ms
1 class Solution { 2 public: 3 bool isHappy(int n){ 4 set<int> s; 5 int recur = compute(n); 6 while(true){ 7 if(recur == 1) return true; 8 else{ 9 if(s.find(recur) != s.end()) return false; 10 else{ 11 s.insert(recur); 12 recur = compute(recur); 13 } 14 } 15 } 16 } 17 int compute(int n){ 18 int sum = 0; 19 while(n){ 20 int temp = n % 10; 21 sum += temp * temp; 22 n /= 10; 23 } 24 return sum; 25 } 26 };
Runtime: 4ms
1 class Solution { 2 private: 3 int compute(int n){ 4 if(n == 0) return n; 5 6 int result = 0; 7 while(n){ 8 int temp = n % 10; 9 result += temp * temp; 10 n /= 10; 11 } 12 return result; 13 } 14 public: 15 bool isHappy(int n) { 16 unordered_map<int, int> m; 17 18 while(n != 1){ 19 n = compute(n); 20 if(m.find(n) != m.end()) 21 return false; 22 else 23 m[n] = n; 24 } 25 return true; 26 } 27 };