Reverse bits of a given 32 bits unsigned integer.
For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000).
Follow up:
If this function is called many times, how would you optimize it?
Analyse:
Extract the right-most bit every time, then put it at the corresponding left place in m.
Pay attention to the place of m = (m<<1)
1 class Solution { 2 public: 3 uint32_t reverseBits(uint32_t n) { 4 uint32_t m = 0; 5 for(int i = 0; i < 32; i++){ 6 m = (m << 1); 7 m = (n & 1) | m; 8 n = (n >> 1); 9 } 10 return m; 11 } 12 };