业务查询缓慢,要求优化查询速度,优化步骤一一枚举出来,防止忘了。
总结:
1、尽量让SQL都使用索引,不要存在in这种不走索引的写法
2、适当的时候,可以将子查询优化成为表连接
原SQL:
SELECT tab2.quoteOrderId, tab2.quoteOrderNumber, tab2.userUpdateTpye, tab2.quoteTitle, DATE_FORMAT( tab2.quoteClosingDate, '%Y-%m-%d' ) AS quoteClosingDate, DATE_FORMAT( tab2.expectedReceivingDate, '%Y-%m-%d' ) AS expectedReceivingDate, tab2.totalPrice, tab2.quoteDate, tab2.user_id AS clientCompany, tab2.type FROM ( SELECT tab.quoteOrderId, tab.quoteOrderNumber, tab.userUpdateTpye, tab.quoteTitle, tab.quoteClosingDate, tab.expectedReceivingDate, tab.totalPrice, tab.quoteDate, tab.user_id, ( CASE WHEN TAB.countNum = TAB.notApprovedCount THEN 0 WHEN TAB.countNum = adoptCount THEN 2 ELSE 1 END ) AS type FROM ( SELECT t1.id AS quoteOrderId, t1.quote_order_number AS quoteOrderNumber, t1.user_update_tpye AS userUpdateTpye, t1.quote_title AS quoteTitle, t1.quote_closing_date AS quoteClosingDate, t1.expected_receiving_date AS expectedReceivingDate, SUM( CASE WHEN t3.approval_status IS NULL THEN 1 ELSE 0 END ) AS notApprovedCount, SUM( CASE t3.approval_status WHEN '1' THEN 1 ELSE 0 END ) AS adoptCount, SUM( CASE t3.approval_status WHEN '2' THEN 1 ELSE 0 END ) AS refuseCount, count( 1 ) countNum, SUM( t2.amount * IFNULL( t3.bj_unit_price_including_tax, 0 )) AS totalPrice, t1.quote_date AS quoteDate, t4.user_id FROM quote_order_info t1 LEFT JOIN quote_order_pro_info t2 ON t1.id = t2.quote_order_info_id LEFT JOIN quote_bj_order_pro_info t3 ON t3.id IN ( SELECT MAX( id ) FROM quote_bj_order_pro_info WHERE quote_order_pro_info_id = t2.id GROUP BY quote_order_pro_info_id ) AND t3.approval_status = 1 LEFT JOIN quote_order_user_info t4 ON t4.quote_order_info_id = t1.id GROUP BY t1.id, t4.user_id ) AS tab ) AS tab2
简单理解sql,业务sql嵌套较多,拆分sql,分段,感觉外层无法优化,也就是说优化点要集中在内层sql:
SELECT t1.id AS quoteOrderId, t1.quote_order_number AS quoteOrderNumber, t1.user_update_tpye AS userUpdateTpye, t1.quote_title AS quoteTitle, t1.quote_closing_date AS quoteClosingDate, t1.expected_receiving_date AS expectedReceivingDate, SUM( CASE WHEN t3.approval_status IS NULL THEN 1 ELSE 0 END ) AS notApprovedCount, SUM( CASE t3.approval_status WHEN '1' THEN 1 ELSE 0 END ) AS adoptCount, SUM( CASE t3.approval_status WHEN '2' THEN 1 ELSE 0 END ) AS refuseCount, count( 1 ) countNum, SUM( t2.amount * IFNULL( t3.bj_unit_price_including_tax, 0 )) AS totalPrice, t1.quote_date AS quoteDate, t4.user_id FROM quote_order_info t1 LEFT JOIN quote_order_pro_info t2 ON t1.id = t2.quote_order_info_id LEFT JOIN quote_bj_order_pro_info t3 ON t3.id IN ( SELECT MAX( id ) FROM quote_bj_order_pro_info WHERE quote_order_pro_info_id = t2.id GROUP BY quote_order_pro_info_id ) AND t3.approval_status = 1 LEFT JOIN quote_order_user_info t4 ON t4.quote_order_info_id = t1.id GROUP BY t1.id, t4.user_id
原sql速率:12.4s
发现问题1:
圈出来的这个sql,in可以改为=号, 原因:分组条件是quote_order_pro_info_id ,且quote_order_pro_info_id有限制= t2.id,也就是说这个group by是多此一举,聚合得到的值只有一个
修正sql后:
LEFT JOIN quote_bj_order_pro_info t3 ON t3.id = ( SELECT MAX( id ) FROM quote_bj_order_pro_info WHERE quote_order_pro_info_id = t2.id )
查询速率:0.175s
优化点2:子查询优化为表连接
子查询会导致外层查询使用不到索引
提取步骤:
提取到与t3同级,也就是与t2同级,使用的t2的条件就应该变为join 的on 条件,因此除了查询出max(id)之外,分组条件 quote_order_pro_info_id 也要查询出来作为连接条件
t3 的id = 查询列的maxId,则是t3关联t5的关联列在on中体现
修正后sql:
left join (SELECT MAX(id) maxId, quote_order_pro_info_id FROM quote_bj_order_pro_info group by quote_order_pro_info_id) t5 on t5.quote_order_pro_info_id = t2.id LEFT JOIN quote_bj_order_pro_info t3 ON t3.id = t5.maxId AND t3.approval_status = 1
查询速率:0.068s
欢迎朋友有有趣的案例发表出来一起探讨