输入一棵二叉树,求该树的深度。从根结点到叶结点依次经过的结点(含根、叶结点)形成树的一条路径,最长路径的长度为树的深度
解题思路
递归写法,比较简单
public class Solution {
public int TreeDepth(TreeNode root) {
if(root == null) {
return 0;
}
int left = TreeDepth(root.left);
int right = TreeDepth(root.right);
return Math.max(left, right) + 1;
}
}
非递归写法
depth 是当前结点所在的层数,count 是已经遍历过的结点数,nextCount 是下层的结点总数,当 count == nextCount 的时候,代表本层的节点已经遍历完毕
import java.util.LinkedList;
import java.util.Queue;
public class Solution {
public int TreeDepth(TreeNode root) {
if(root == null) {
return 0;
}
Queue<TreeNode> queue = new LinkedList<>();
queue.add(root);
int depth = 0, count = 0, nextCount = 1;
while(queue.size() != 0) {
TreeNode top = queue.poll();
count++;
if(top.left != null) {
queue.add(top.left);
}
if(top.right != null) {
queue.add(top.right);
}
if(count == nextCount) {
nextCount = queue.size();
count = 0;
depth++;
}
}
return depth;
}
}