• NOJ Physics


    Physics

    时间限制(普通/Java) : 1000 MS/ 3000 MS          运行内存限制 : 65536 KByte
    总提交 : 49            测试通过 : 41 

    题目描述

    A particle has initial constant velocity. For a particle with initial velocity v find the displacement of that

    particle if the time t is doubled.




    输入

    The input will contain two integers in each line. Each line makes one set of input. These two integers

    denote the value of v (-10000 <= v <= 10000) and t(0<=t<= 500) ( t means at the time the particle gains

    that velocity)


    输出

    For each line of input print a single integer in one line denoting the displacement in double of that time.

    样例输入

    0 0
    5 12

    样例输出

    0
    120

    提示

    undefined


    分析:看懂题目意思就够了。

    <span style="font-size:12px;">#include<iostream>
    #include<cstdlib>
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    using namespace std;
    int v,t,dis;
    int main()
    {
        while(~scanf("%d%d",&v,&t))
        {
            dis=v*t*2;
            printf("%d
    ",dis);
        }
    }</span>

    版权声明:本文为博主原创文章,未经博主允许不得转载。

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  • 原文地址:https://www.cnblogs.com/Tobyuyu/p/4965453.html
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