贪心 BestCoder Round #39 1001 Delete

题目传送门

/*
    贪心水题：找出出现次数>1的次数和res，如果要减去的比res小，那么总的不同的数字tot不会少；
            否则再在tot里减去多余的即为答案
    用set容器也可以做，思路一样
*/
#include <cstdio>
#include <iostream>
#include <cstring>
#include <string>
#include <algorithm>
using namespace std;

const int MAXN = 1e4 + 10;
const int INF = 0x3f3f3f3f;
int cnt[110];

int main(void)        //BestCoder Round #39 1001 Delete
{
    //freopen ("1001.in", "r", stdin);

    int n;
    while (scanf ("%d", &n) == 1)
    {
        int k;
        memset (cnt, 0, sizeof (cnt));

        int tot = 0, res = 0, x;
        for (int i=1; i<=n; ++i)
        {
            scanf ("%d", &x);
            if (cnt[x] == 0)    tot++;
            else if (cnt[x] >= 1)    res++;
            cnt[x]++;
        }

        scanf ("%d", &k);
        if (res >= k)    printf ("%d
", tot);
        else    printf ("%d
", tot - (k - res));
    }

    return 0;
}

#include <cstdio>
#include <iostream>
#include <cstring>
#include <string>
#include <algorithm>
#include <set>
using namespace std;

int main(void)        //BestCoder Round #39 1001 Delete
{
    //freopen ("1001.in", "r", stdin);

    set<int> S;
    int n, k;

    while (cin >> n)
    {
        S.clear ();
        int x;
        for (int i=1; i<=n; ++i)
        {
            cin >> x;    S.insert (x);
        }

        cin >> k;
        cout << ((n-S.size () <= k) ? n - k : S.size ()) << endl;
    }

    return 0;
}