• 线性规划与网络流24题 运输问题(最裸的费用流了)


    存费用流模板

    用sfpa算出最小费用和路径,沿这条路径增广

      1 const
      2         inf=maxlongint;
      3 var
      4         n,m:longint;
      5         map,a,w:array[0..120,0..120]of longint;
      6 
      7 procedure init;
      8 var
      9         i,j:longint;
     10 begin
     11         read(m,n);
     12         for i:=1 to m do
     13           read(map[0,i]);
     14         for i:=1 to n do
     15           read(map[m+i,n+m+1]);
     16         for i:=1 to m do
     17           for j:=1 to n do
     18             begin
     19               read(w[i,m+j]);
     20               w[m+j,i]:=-w[i,m+j];
     21               map[i,m+j]:=inf;
     22             end;
     23 end;
     24 
     25 var
     26         flag,d,dis,pre:array[0..120]of longint;
     27         time:longint;
     28 
     29 function spfa:boolean;
     30 var
     31         i,head,tail,num:longint;
     32 begin
     33         head:=1;
     34         tail:=1;
     35         num:=1;
     36         inc(time);
     37         for i:=1 to n+m+1 do
     38           dis[i]:=inf;
     39         dis[0]:=0;
     40         d[1]:=0;
     41         flag[0]:=time;
     42         while num>0 do
     43           begin
     44                 for i:=1 to n+m+1 do
     45                   if (a[d[head],i]>0)and(dis[d[head]]+w[d[head],i]<dis[i]) then
     46                   begin
     47                         dis[i]:=dis[d[head]]+w[d[head],i];
     48                         pre[i]:=d[head];
     49                         if flag[i]<>time then
     50                         begin
     51                           flag[i]:=time;
     52                           inc(num);
     53                           tail:=tail mod(n+m+1)+1;
     54                           d[tail]:=i;
     55                         end;
     56                   end;
     57                 flag[d[head]]:=time-1;
     58                 head:=head mod(n+m+1)+1;
     59                 dec(num);
     60           end;
     61         if dis[n+m+1]=inf then exit(false);
     62         exit(true);
     63 end;
     64 
     65 procedure work;
     66 var
     67         i,j,aug,ans:longint;
     68 begin
     69         for i:=0 to n+m+1 do
     70           for j:=0 to n+m+1 do
     71             a[i,j]:=map[i,j];
     72         ans:=0;
     73         while spfa do
     74           begin
     75             aug:=inf;
     76             i:=n+m+1;
     77             while i<>0 do
     78               begin
     79                 j:=pre[i];
     80                 if a[j,i]<aug then aug:=a[j,i];
     81                 i:=j;
     82               end;
     83             inc(ans,dis[n+m+1]*aug);
     84             i:=n+m+1;
     85             while i<>0 do
     86               begin
     87                 j:=pre[i];
     88                 inc(a[i,j],aug);
     89                 dec(a[j,i],aug);
     90                 i:=j;
     91               end;
     92           end;
     93         writeln(ans);
     94         ans:=0;
     95         for i:=1 to m do
     96           for j:=1 to n do
     97             begin
     98               w[i,j+m]:=-w[i,j+m];
     99               w[j+m,i]:=-w[j+m,i];
    100             end;
    101         for i:=0 to n+m+1 do
    102           for j:=0 to n+m+1 do
    103             a[i,j]:=map[i,j];
    104         ans:=0;
    105         while spfa do
    106           begin
    107             aug:=inf;
    108             i:=n+m+1;
    109             while i<>0 do
    110               begin
    111                 j:=pre[i];
    112                 if a[j,i]<aug then aug:=a[j,i];
    113                 i:=j;
    114               end;
    115             inc(ans,dis[n+m+1]*aug);
    116             i:=n+m+1;
    117             while i<>0 do
    118               begin
    119                 j:=pre[i];
    120                 inc(a[i,j],aug);
    121                 dec(a[j,i],aug);
    122                 i:=j;
    123               end;
    124           end;
    125         writeln(-ans);
    126 end;
    127 
    128 begin
    129     assign(input,'trans.in');
    130     reset(input);
    131     assign(output,'trans.out');
    132     rewrite(output);
    133         init;
    134         work;
    135     close(input);
    136     close(output);
    137 end.
    View Code
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  • 原文地址:https://www.cnblogs.com/Randolph87/p/3602203.html
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