Given a 32-bit signed integer, reverse digits of an integer.
Example 1:
Input: 123 Output: 321
Example 2:
Input: -123 Output: -321
Example 3:
Input: 120 Output: 21
Note:
Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231, 231 − 1]. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.
题意:翻转一个int数,注意两点,一是越界,而是0的问题
class Solution { public int reverse(int x) { if (x == -2147483648) return 0; boolean flag = false; if (x < 0) flag = true; x = Math.abs(x); long res = 0; while (x != 0) { res = res*10 + x%10; x /= 10; if (res > Integer.MAX_VALUE) { res = 0; return 0; } } if (flag) return (int)-res; return (int)res; } }