• numpy对图像的处理演示


    pip3 install pillow
    
    from PIL import Image
    import numpy as np
    im=np.array(Image.open('timg.jpg'))
    
    print(im.shape,im.dtype)
    
    from PIL import Image
    import numpy as np
    im=np.array(Image.open('timg.jpg'))
    print(im.shape,im.dtype)
    b=[255,255,255]-im
    a=Image.fromarray(b.astype('uint8'))
    a.save('new-timg.jpg')
    

      运算结果:

    D:python3python.exe D:/python入门/数据可视化/numpy_demo/的mo.py
    (749, 1200, 3) uint8
    
    Process finished with exit code 0  


    # from PIL import Image
    # import numpy as np
    # im=np.array(Image.open('timg.jpg'))
    # print(im.shape,im.dtype)
    # b=im*(100/255)+150
    # a=Image.fromarray(b.astype('uint8'))
    # a.save('new-timg.jpg')
    
    
    # from PIL import Image
    # import numpy as np
    # im=np.array(Image.open('timg.jpg'))
    # print(im.shape,im.dtype)
    # b=255-im
    # a=Image.fromarray(b.astype('uint8'))
    # a.save('new-timg.jpg')
    
    from PIL import Image
    import numpy as np
    im=np.array(Image.open('timg.jpg'))
    print(im.shape,im.dtype)
    b=255*(im/255)**2
    a=Image.fromarray(b.astype('uint8'))
    a.save('new-timg.jpg')
    View Code

     手绘风格的效果

    from PIL import Image
    import numpy as np
    
    a = np.asarray(Image.open('timg.jpg').convert('L')).astype('float')
    
    depth = 8.  # (0-100)
    grad = np.gradient(a)  # 取图像灰度的梯度值
    grad_x, grad_y = grad  # 分别取横纵图像梯度值
    grad_x = grad_x * depth / 100.
    grad_y = grad_y * depth / 100.
    A = np.sqrt(grad_x ** 2 + grad_y ** 2 + 1.)
    uni_x = grad_x / A
    uni_y = grad_y / A
    uni_z = 1. / A
    
    vec_el = np.pi / 2.2  # 光源的俯视角度,弧度值
    vec_az = np.pi / 4.  # 光源的方位角度,弧度值
    dx = np.cos(vec_el) * np.cos(vec_az)  # 光源对x 轴的影响
    dy = np.cos(vec_el) * np.sin(vec_az)  # 光源对y 轴的影响
    dz = np.sin(vec_el)  # 光源对z 轴的影响
    
    b = 255 * (dx * uni_x + dy * uni_y + dz * uni_z)  # 光源归一化
    b = b.clip(0, 255)
    
    im = Image.fromarray(b.astype('uint8'))  # 重构图像
    im.save('b.jpg')
    View Code
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  • 原文地址:https://www.cnblogs.com/Mengchangxin/p/10066848.html
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