pat1121-1131

1121

#include<cmath>
#include<map>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<set>
#include<vector>
#include<queue>
#include<stack>
#include<algorithm>
using namespace std;
typedef long long ll;
const int N = 1e6+5;
const int INF = 0x3f3f3f3f;
#define MP(x, y) make_pair(x, y)

int pai[N];
int a[N];
int has[N];
int ord[N];
int main() {
  int n;
  while(~scanf("%d", &n)) {
    memset(pai, -1, sizeof(pai));
    for(int i = 0; i < n; ++i) {
      int a, b; scanf("%d%d", &a, &b);
      pai[a] = b; pai[b] = a;
    }

    int m; scanf("%d", &m);
    for(int i = 0; i < m; ++i) {
      scanf("%d", &a[i]);
      has[a[i]] ++; if(pai[a[i]] != -1) has[pai[a[i]]] ++;
    }
    int tot = 0;
    for(int i = 0; i < m; ++i) {
      if(has[a[i]] == 1) {
        ord[tot ++] = a[i];
      }
    }

    sort(ord, ord + tot);
    printf("%d
", tot);
    for(int i = 0; i < tot; ++i) {
      if(i) printf(" ");
      printf("%05d", ord[i]);
    }
    if(tot) printf("
");
  }
  return 0;
}

1122 我把爆搜都写完了，才发现这题的圈顺序是给定的，我爆搜就不删了

#include<cmath>
#include<map>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<set>
#include<vector>
#include<queue>
#include<stack>
#include<algorithm>
using namespace std;
typedef long long ll;
const int N = 205;
const int INF = 0x3f3f3f3f;
#define MP(x, y) make_pair(x, y)

struct Node{
  int to, nx;
}E[N*N*2];
int mp[N][N];
int head[N], tot;
void add(int fr, int to) {
  E[tot].to = to; E[tot].nx = head[fr]; head[fr] = tot ++;
}
set<int> st;
int suc;
void dfs(int l, int r) {
  printf("%d %d
", l, r);
  if(suc) return;
  if(st.size() == 0) {
    if(mp[l][r]) suc = 1;
    return;
  } 
  if(st.size() == 1) {
    int tt = *st.begin();
    if(mp[l][tt] && mp[r][tt]) {
      suc = 1;
    } 
    return;
  }


  vector<int> ch1; vector<int> ch2;
  for(int i = head[l]; ~i; i = E[i].nx) {
    if(st.find(E[i].to) != st.end()) {
      ch1.push_back(E[i].to);
    }
  }
  if(l == r) {
    for(int i = 0; i < ch1.size() && !suc; ++i) {
      for(int j = i+1; j < ch1.size() && !suc; ++j) {
        st.erase(ch1[i]); st.erase(ch1[j]);
        dfs(ch1[i], ch1[j]);
        st.insert(ch1[i]); st.insert(ch1[j]);
      }
    }
    return;
  }
  for(int i = head[r]; ~i; i = E[i].nx) {
    if(st.find(E[i].to) != st.end()) {
      ch2.push_back(E[i].to);
    }
  }

  for(int i = 0; i < ch1.size() && !suc; ++i) {
    for(int j = 0; j < ch2.size() && !suc; ++j) {
      if(ch1[i] != ch2[j]) {
        st.erase(ch1[i]); st.erase(ch2[j]);
        dfs(ch1[i], ch2[j]);
        st.insert(ch1[i]); st.insert(ch2[j]);
      }
    }
  }

}
int main() {
  int n,m;
  while(~scanf("%d %d", &n, &m)) {
    memset(head, -1, sizeof(head));
    tot = 0;

    for(int i = 0; i < m; ++i) {
      int a, b; scanf("%d %d", &a, &b);
      add(a, b); add(b, a);
      mp[a][b] = mp[b][a] = 1;
    }


    int k; scanf("%d", &k);
    while(k --) {
      int a; scanf("%d", &a);
      int fl = 1;
      st.clear();
      int pre = -1;
      int St = -1;

      for(int i = 0; i < a; ++i) {
        int b; scanf("%d", &b);
        if(St == -1) St = b;
        if(st.find(b) != st.end() && i != a-1) fl = 0;
        if(i == a-1 && St != b) fl = 0;
        if(~pre && !mp[b][pre]) fl = 0;
        pre = b;
        st.insert(b);
      }

    //  int tt = *st.begin(); st.erase(tt);
    //  suc = 0;
    //  dfs(tt, tt);

      if(fl && a > 4) printf("YES
");
      else printf("NO
");
    }
  }
  return 0;
}

1123 和之前一道avl类似

#include<cmath>
#include<map>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<set>
#include<vector>
#include<queue>
#include<algorithm>
using namespace std;
typedef long long ll;
const int N = 25;
const int INF = 0x3f3f3f3f;
#define MP(x, y) make_pair(x, y)

int root;
int num[N];
int L[N], R[N], fa[N];
int n;

void insert(int x, int tag) {
  //  printf("tag: %d
", x);
  if(!root) {
    root = tag; fa[tag] = tag; return; 
  }
  if(num[x] > num[tag]) {
    if(!L[x])  L[x] = tag, fa[tag] = x;
    else insert(L[x], tag);
  }else {
    if(!R[x])  R[x] = tag, fa[tag] = x;
    else insert(R[x], tag);
  }
}


struct Node{
  int po, val;
  Node(int a=0, int b=0):po(a), val(b){}
}E[10];
int cmp(Node a,Node b) {
  return a.val < b.val;
}

void LL(int x) {
  //  printf("LL
");
  int fart = fa[fa[x]];
  int t1 = x; int t2 = R[x]; int t3 = fa[x];
  fa[t1] = 0; fa[t2] = 0; fa[t3] = 0;
  R[t1] = t3; fa[t3] = t1;
  L[t3] = t2; fa[t2] = t3;

  if(t3 == root) {
    root = t1; fa[t1] = t1;
  }else if(L[fart] == t3) {
    L[fart] = t1; fa[t1] = fart;
  }else R[fart] = t1, fa[t1] = fart;
}
void RR(int x) {
  //  printf("RR
");
  int fart = fa[fa[x]];
  int t1 = x; int t2 = L[x]; int t3 = fa[x];
  fa[t1] = 0; fa[t2] = 0; fa[t3] = 0;
  L[t1] = t3; fa[t3] = t1;
  R[t3] = t2; fa[t2] = t3;

  if(t3 == root) {
    root = t1; fa[t1] = t1;
  }else if(L[fart] == t3) {
    L[fart] = t1; fa[t1] = fart;
  }else R[fart] = t1, fa[t1] = fart;
}
void LR(int x, int tag) {
  //  printf("LR
");

  int fart = fa[fa[x]];
  int t1 = x; int t2 = R[x]; int t3 = fa[x];
  int a1 = L[t2]; int a2 = R[t2];

  fa[t1] = 0; fa[t2] = 0; fa[t3] = 0;
  R[t1] = 0; L[t3] = 0;
  L[t2] = t1; fa[t1] = t2;
  R[t2] = t3; fa[t3] = t2;
  if(t3 == root) {
    root = t2; fa[t2] = t2;
  }else if(L[fart] == t3) {
    L[fart] = t2; fa[t2] = fart;
  }else {
    R[fart] = t2; fa[t2] = fart;
  }

  if(a1) insert(root, a1);
  if(a2) insert(root, a2);
}
void RL(int x, int tag) {
  //  printf("RL
");
  int fart = fa[fa[x]];
  int t1 = x; int t2 = L[x]; int t3 = fa[x];
  int a1 = L[t2]; int a2 = R[t2];

  L[t1] = 0; R[t3] = 0;
  fa[t1] = 0; fa[t2] = 0; fa[t3] = 0;
  L[t2] = t3; fa[t3] = t2;
  R[t2] = t1; fa[t1] = t2;
  //   printf("hh %d %d %d
", num[t1], num[t2], num[t3]);
  if(t3 == root) {
    root = t2; fa[t2] = t2;
  }else if(L[fart] == t3) {
    L[fart] = t2; fa[t2] = fart;
  }else {
    R[fart] = t2; fa[t2] = fart;
  }
  //  printf("hh %d %d", fart, R[fart]);
  if(a1) insert(root, a1);
  if(a2) insert(root, a2);
}
void fix(int x) {
  int rt = fa[fa[x]]; int fart = fa[rt];
  if( (L[rt]==0) + (R[rt]==0) == 1) {
    int tot = 0;
    for(int i = 0, tt = x; i < 3; ++i) {
      E[tot++] = Node(tt, num[tt]); 
      tt = fa[tt];
    }  
    sort(E, E+tot, cmp);
    L[E[1].po] = E[0].po; fa[E[0].po] = E[1].po;  
    R[E[1].po] = E[2].po; fa[E[2].po] = E[1].po;
    L[E[0].po] = 0; R[E[0].po] = 0;
    L[E[2].po] = 0; R[E[2].po] = 0;

    if(root == rt) {
      root = E[1].po; fa[root] = root;
    }else if(L[fart] == rt) {
      L[fart] = E[1].po; fa[E[1].po] = fart;
    }else {
      R[fart] = E[1].po; fa[E[1].po] = fart;
    }
  }else {
    //  printf("%d %d %d
", x, rt, fa[rt]);
    if     (L[fa[rt]] == rt && L[rt] == fa[x] ) LL(rt);
    else if(R[fa[rt]] == rt && R[rt] == fa[x] ) RR(rt);
    else if(L[fa[rt]] == rt && R[rt] == fa[x] ) LR(rt, x);
    else if(R[fa[rt]] == rt && L[rt] == fa[x] ) RL(rt, x);
  }
}
void test(int x, int pre) {
  printf("%d from %d
", x, pre);
  if(L[x]) test(L[x], x);
  if(R[x]) test(R[x], x);
}

int height[N]; int tag;
void dfs(int x) {
  int t1 = 0, t2 = 0;
  if(L[x]) dfs(L[x]), t1 = height[L[x]];
  if(R[x]) dfs(R[x]), t2 = height[R[x]];
  height[x] = max(t1, t2)+1;
  if( abs(t1- t2) > 1  && !tag) tag = x;
}
void solve(int x) {
  //  printf("do %d
", x);
  memset(height, 0, sizeof(height));
  tag = 0;
  dfs(root);
  if(tag) {
    int t1 = tag;
    if(height[L[t1]] > height[R[t1]]) t1 = L[t1];
    else t1 = R[t1];

    if(height[L[t1]] > height[R[t1]]) t1 = L[t1];
    else t1 = R[t1];

    if(height[L[t1]] > height[R[t1]]) t1 = L[t1];
    else if(height[L[t1]] < height[R[t1]]) t1 = R[t1];

    //  printf("%d %d
", tag, t1);
    fix(t1);
  }
  //  test(root, root);
  //  printf("
");
}
void bfs(int x) {
  int all = 0;
  queue<int> Q;
  Q.push(x);
  while(Q.front() != 0) {
    int po = Q.front(); Q.pop();
    all ++;
    Q.push(L[po]); Q.push(R[po]);
  }
  while(!Q.empty()) Q.pop();
  Q.push(x);
  int nn = 0;
  while(!Q.empty()) {
    int po = Q.front(); Q.pop();
    if(!nn) nn = 1; else printf(" ");
    printf("%d", num[po]);
    if(L[po]) Q.push(L[po]);
    if(R[po]) Q.push(R[po]);
  }
  printf("
");
  if(all == n) printf("YES
");
  else printf("NO
");

}
int main() {
  while(~scanf("%d", &n)) {
    root = 0;
    memset(fa, 0, sizeof(fa));
    memset(L, 0, sizeof(L));
    memset(R, 0, sizeof(R));

    for(int i = 1; i <= n; ++i) {
      scanf("%d", &num[i]);
      insert(root, i);
      solve(i);
      //  fa[root] = root;
      //  check(root);
    }
  //  printf("hh
");
    bfs(root);
  //  printf("%d
", num[root]);
  }
  return 0;
}

1124

#include<cmath>
#include<map>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<set>
#include<vector>
#include<queue>
#include<algorithm>
using namespace std;
typedef long long ll;
const int N = 25;
const int INF = 0x3f3f3f3f;
#define MP(x, y) make_pair(x, y)

map<string, int> mp;
int main() {
  int m, n, s;
  while(~scanf("%d %d %d", &m, &n, &s)) {
    int won = s;
    int all = 0;
    mp.clear();
    for(int i = 1, j = 1; i <= m; ++i) {
      char s[10]; scanf("%s", s);
      if(j == won) {
        if(mp.find(s) == mp.end()) printf("%s
", s), won += n, all ++;
        else j --;
        mp[s] = 1;
      }
      j++;
    }
    if(!all) printf("Keep going...
");
  }
  return 0;
}

1125 讲道理我没有读懂题之前 = =我以为在你们选几个组成不就行了，直接选两个最大的

#include<cmath>
#include<map>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<set>
#include<vector>
#include<queue>
#include<algorithm>
using namespace std;
typedef long long ll;
const int N = 1e4+5;
const int INF = 0x3f3f3f3f;
#define MP(x, y) make_pair(x, y)

int a[N];
int main() {
  int n;
  while(~scanf("%d", &n)) {
    for(int i = 0; i < n; ++i) scanf("%d", &a[i]);
    sort(a, a + n);
    int ans = a[0];
    for(int i = 1; i < n; ++i) {
      ans = (ans + a[i]) / 2;
    }
    printf("%d
", ans);
  }
  return 0;
}

1126需先判断下图的连通性

#include<cmath>
#include<map>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<set>
#include<vector>
#include<queue>
#include<algorithm>
using namespace std;
typedef long long ll;
const int N = 505;
const int INF = 0x3f3f3f3f;
#define MP(x, y) make_pair(x, y)

struct Node{
  int to, nx;
}E[N*N*2];
int head[N], tot;
int vis[N];
void add(int fr, int to) {
  E[tot].to = to; E[tot].nx = head[fr]; head[fr] = tot ++;
}
void dfs(int x) {
  for(int i = head[x]; ~i; i = E[i].nx) {
    int to = E[i].to;
    if(!vis[to]) {
      vis[to] = 1;
      dfs(to);
    }
  }
}
int in[N];
int main() {
  int n, m;
  while(~scanf("%d %d", &n, &m)) {
    memset(in, 0, sizeof(in));
    memset(vis, 0, sizeof(vis));
    memset(head, -1, sizeof(head)); tot = 0;

    for(int i = 0; i < m; ++i) {
      int a, b; scanf("%d %d", &a, &b);
      add(a, b); add(b, a); 
      in[a] ++; in[b] ++;
    }
    vis[1] = 1; 
    dfs(1);

    int fl = 1;
    for(int i = 1; i <= n; ++i) {
      if(!vis[i]) {
        fl = 0; break;
      }
    }

    int odd = 0; int even = 0;
    for(int i = 1; i <= n; ++i) {
      if(in[i] % 2 == 0) even ++;
      else odd ++;
    }

    for(int i = 1; i <= n; ++i) {
      if(i != 1) printf(" ");
      printf("%d", in[i]);
    } printf("
");

    if(odd == 0 && fl) printf("Eulerian
");
    else if(odd == 2 && fl) printf("Semi-Eulerian
");
    else printf("Non-Eulerian
");


  }
  return 0;
}

1127

#include<cmath>
#include<map>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<set>
#include<vector>
#include<queue>
#include<algorithm>
using namespace std;
typedef long long ll;
const int N = 35;
const int INF = 0x3f3f3f3f;
#define MP(x, y) make_pair(x, y)

int in[N];
int post[N];
map<int, int> L;
map<int, int> R;

int solve(int LL, int RR, int l, int r) {
  if(l > r) return 0;
     else if(l == r) return post[l];

  int tag = post[r];
  int po = 0;
  for(int i = LL; i <= RR; ++i) {
    if(in[i] == tag) {
      po = i; break;
    }
  }
  int _po = l + (po-1-LL);

  L[tag] = solve(LL, po-1, l, _po);
     R[tag] = solve(po+1, RR, _po+1, r-1);

  return tag;
}
void bfs(int x) {
  queue<int> Q;
  Q.push(x);
  int fl = 1;

  while(!Q.empty()) {
    vector<int> vc;
    int ed = Q.size();
    for(int i = 0; i < ed; ++i) {
      int po = Q.front(); Q.pop();
      vc.push_back(po);
      if(L[po]) Q.push(L[po]);
      if(R[po]) Q.push(R[po]);
    }

    if(fl) for(int i = vc.size()-1; i >= 0; --i) {
      if(vc[i] != x) printf(" ");
      printf("%d", vc[i]);
    }else for(int i = 0; i < vc.size(); ++i) {
      if(vc[i] != x) printf(" ");
      printf("%d", vc[i]);
    }
    fl ^= 1;
  }
  printf("
");
}
int main() {
  int n;
  while(~scanf("%d", &n)) {

    for(int i = 1; i <= n; ++i) {
      scanf("%d", &in[i]);
    }


    for(int i = 1; i <= n; ++i) scanf("%d", &post[i]);

    int root = solve(1, n, 1, n);

    bfs(root);  
  }
  return 0;
}

1128

#include<cmath>
#include<map>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<set>
#include<vector>
#include<queue>
#include<algorithm>
using namespace std;
typedef long long ll;
const int N = 1005;
const int INF = 0x3f3f3f3f;
#define MP(x, y) make_pair(x, y)

int dia1[N*2];
int row[N];
int dia2[N*2];

int main() {
  int k;
  while(~scanf("%d", &k)) {

    for(int i = 1; i <= k; ++i) {
      int a; scanf("%d", &a);
      int fl = 1;

      for(int j = 1; j <= a; ++j) {
        int b; scanf("%d", &b);
        int t1 = b; int t2 = b-j + a; int t3 = b+j;
        if(row[t1] == i|| dia1[t2] == i || dia2[t3] == i ) fl = 0;

        row[t1] = i; dia1[t2] = i; dia2[t3] = i;
      }  

      if(fl) printf("YES
");
      else printf("NO
");
    }

  }
  return 0;
}

1129

#include<cmath>
#include<map>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<set>
#include<vector>
#include<queue>
#include<algorithm>
using namespace std;
typedef long long ll;
const int N = 5e4+5;
const int INF = 0x3f3f3f3f;
#define MP(x, y) make_pair(x, y)

int has[N];
int a[N];
struct Node{
  int nu, po;
  Node(int a=0, int b=0):nu(a), po(b) {}
  bool operator <(const Node &T) const  {
    if(nu != T.nu) return nu > T.nu;
    else return po < T.po;
  }
};
set<Node> st;
set<Node> ::iterator it;

int main() {
  int n, k;
  while(~scanf("%d %d", &n, &k)) {
    st.clear();
    memset(has, 0, sizeof(has));

    for(int i = 1; i <= n; ++i) scanf("%d", &a[i]);

    has[a[1]] ++;
    st.insert(Node(has[a[1]], a[1]));

    for(int i = 2; i <= n; ++i) {
      printf("%d: ", a[i]);
      int cnt = 0;
      for(it = st.begin(); it != st.end(); ++it) {
        if(it != st.begin()) printf(" ");
        printf("%d", (*it).po);
        cnt ++;
        if(cnt >= k) break;
      }
      printf("
");


      has[a[i]] ++;

      it = st.find(Node(has[a[i]]-1, a[i]) );
      if( it != st.end() ) st.erase(it), st.insert(Node(has[a[i]], a[i]));
      else {
        st.insert(Node(has[a[i]], a[i]));
        if(st.size() > k) st.erase(--st.end());
      }

    }  
  }
  return 0;
}

1030

#include<cmath>
#include<map>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<set>
#include<vector>
#include<queue>
#include<algorithm>
using namespace std;
typedef long long ll;
const int N = 25;
const int INF = 0x3f3f3f3f;
#define MP(x, y) make_pair(x, y)

char num[N][15];
int dep[N];
int root;
int L[N], R[N];

void dfs(int x) {
  if(x != root && L[x] + R[x]) printf("(");
  if(L[x]) dfs(L[x]);
  printf("%s", num[x]);
  if(R[x]) dfs(R[x]);
  if(x != root && L[x] + R[x]) printf(")");
}
int main() {
  int n;
  while(~scanf("%d", &n)) {
    for(int i = 1; i <= n; ++i) {
      char b[10], c[10];
      scanf("%s %s %s", num[i], b, c);
      int tt;
      if(b[0] != '-') {
        sscanf(b, "%d", &tt);
        L[i] = tt, dep[tt] ++;
      }
      if(c[0] != '-') {
        sscanf(c, "%d", &tt);
        R[i] = tt; dep[tt] ++;
      }
    }
    for(int i = 1; i <= n; ++i) {
      if(!dep[i]) {
        root = i;
        dfs(i);
        break;
      }
    }

    printf("
");


  }
  return 0;
}

1031 最后一题还是花了一点时间，简单来说就是最短路即可，但是中间处理还是有点难的

#include<cmath>
#include<map>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<set>
#include<vector>
#include<queue>
#include<algorithm>
using namespace std;
typedef long long ll;
const int N = 105;
const int M = 1e5+5;

const int INF = 0x3f3f3f3f;
#define MP(x, y) make_pair(x, y)

map<int, int> nam;
map<int, int> ::iterator it;
int _nam[M];
vector<int> input[N];
int n; 
int tol;
struct Node{
  int nx, to, ty;
}E[M*10];
int head[M], tot;
void add(int fr, int to, int ty) {
  E[tot].to = to; E[tot].nx = head[fr]; E[tot].ty = ty; head[fr] = tot++;
}
struct Hode{
  int po, di, ti, ty;
  Hode(int a=0, int b=0, int c=0, int d=0):po(a), di(b), ti(c), ty(d) {}
  bool operator < (const Hode & T) const{
    if(di != T.di) return di > T.di;
    else return ti > T.ti;
  }
};
pair<int, int> pre[M]; int vis[M];
int dis[M], tim[M];
vector<pair<int, int> > ans;

void dfs(int x, int s) {
//  printf("%d %d
", x, _nam[x]);
  if(x == s) {
    return ;
  }
  dfs(pre[x].first, s);
  ans.push_back(MP(x, pre[x].second));
}

void dij(int s, int t) {
//  printf("%d %d
", s, t);
  for(int i = 1; i <= tol; ++i) {
    vis[i] = 0; dis[i] = INF; tim[i] = INF;
  }
  dis[s] = 0; tim[s] = 0;
  priority_queue<Hode> Q;
  Q.push(Hode(s, dis[s], tim[s], INF));
  while(!Q.empty()) {
    int po = Q.top().po; int ty = Q.top().ty; Q.pop();
    if(vis[po]) continue;
    vis[po] = 1;
    for(int i = head[po]; ~i; i = E[i].nx) {
      int to = E[i].to;
         int tt = ty != E[i].ty;  
      if(dis[to] > dis[po] + 1) {
        dis[to] = dis[po] + 1;
        tim[to] = tim[po] + tt;
        pre[to] = MP(po, E[i].ty);
        Q.push(Hode(to, dis[to], tim[to], E[i].ty));
      }else if(dis[to] == dis[po] + 1 && tim[to] > tim[po] + tt )  {
        tim[to] = tim[po] + tt;
        pre[to] = MP(po, E[i].ty);
        Q.push(Hode(to, dis[to], tim[to], E[i].ty));
      }
    }
  }
  ans.clear();
  dfs(t, s);
  printf("%d
", dis[t]);
  int fr = s;
  ans.push_back(MP(INF, INF));
  for(int i = 1; i < ans.size(); ++i) {
    if(ans[i].second != ans[i-1].second) {
      printf("Take Line#%d from %04d to %04d.
", ans[i-1].second, _nam[fr], _nam[ans[i-1].first]);
      fr = ans[i-1].first;
    }
  }
}

int main() {
  while(~scanf("%d", &n)) {
    memset(head, -1, sizeof(head)); tot = 0;

    for(int i = 1; i <= n; ++i) {
      int m; scanf("%d", &m);
      input[i].push_back(m);
      for(int j = 0; j < m; ++j) {
        int b; scanf("%d", &b);
        input[i].push_back(b);
        nam[b] ++;
      }
    }

    tol = 0;
    for(it = nam.begin(); it != nam.end(); ++it) {
      nam[it->first] = ++tol;
      _nam[tol] = it->first;
    }
    // for(int i = 1; i <= tol; ++i) printf("%d:%d ", _nam[i], nam[_nam[i]]); printf("
");

    for(int i = 1; i <= n; ++i) {
      for(int j = 2; j < input[i].size(); ++j) {
        add(nam[input[i][j]], nam[input[i][j-1]], i); add(nam[input[i][j-1]], nam[input[i][j]], i);
      }
    }

    int m; scanf("%d", &m);
    while(m --) {
      int a, b; scanf("%d %d", &a, &b);
      dij(nam[a], nam[b]);
    }  
  }
  return 0;
}