python列表

Python 2.7.10 (default, Oct 14 2015, 16:09:02) 
[GCC 5.2.1 20151010] on linux2
Type "copyright", "credits" or "license()" for more information.
>>> dir(list)
['__add__', '__class__', '__contains__', '__delattr__', '__delitem__', '__delslice__', '__doc__', '__eq__', '__format__', '__ge__', '__getattribute__', '__getitem__', '__getslice__', '__gt__', '__hash__', '__iadd__', '__imul__', '__init__', '__iter__', '__le__', '__len__', '__lt__', '__mul__', '__ne__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__reversed__', '__rmul__', '__setattr__', '__setitem__', '__setslice__', '__sizeof__', '__str__', '__subclasshook__', 'append', 'count', 'extend', 'index', 'insert', 'pop', 'remove', 'reverse', 'sort']
>>> list1=[1,2,3]
>>> list2=[4,5,6]
>>> list3=list1+list2
>>> list3
[1, 2, 3, 4, 5, 6]
>>> list3*=2
>>> list3
[1, 2, 3, 4, 5, 6, 1, 2, 3, 4, 5, 6]
>>> 3 in list3
True
>>> 7 in list3
False
>>> 7 not in list3
True
>>> list4["niha",[2,3],'q']

Traceback (most recent call last):
  File "<pyshell#10>", line 1, in <module>
    list4["niha",[2,3],'q']
NameError: name 'list4' is not defined
>>> list4=["niha",[2,3],'q']
>>> list4
['niha', [2, 3], 'q']
>>> 2 in list4
False
>>> 2 in list[1]

Traceback (most recent call last):
  File "<pyshell#14>", line 1, in <module>
    2 in list[1]
TypeError: 'type' object has no attribute '__getitem__'
>>> 2 in list4[1]
True
>>> list3.count(1)
2
>>> list3.index(2)
1
>>> list3.index(4,1,10)
3
>>> list3.index(4,2,10)
3
>>> list3.reverse()
>>> list3
[6, 5, 4, 3, 2, 1, 6, 5, 4, 3, 2, 1]
>>> 
>>> 
>>> list5=[3,7,4,9,1,8]
>>> list5.sort()
>>> list5
[1, 3, 4, 7, 8, 9]
>>> list5.so

Traceback (most recent call last):
  File "<pyshell#27>", line 1, in <module>
    list5.so
AttributeError: 'list' object has no attribute 'so'
>>> list5.sort(reverse=True)
>>> list5
[9, 8, 7, 4, 3, 1]
>>> 

python自带的sort函数其实有3个参数，都有默认的值，第一个是func，代表解决的算法，python的sort是由归并排序解决的，第二格式key和func想对应。第三个是reverse就是反转，默认的值为false，如果希望、

sort从大到小排序，就将reverse赋值为True，

list链表的复制拷贝

必须要用slice切片赋值，那样cachi开出新的空间创建一个数组，否之直接赋值就相当于c语言中的引用起了一个别名，实际指向的是同一快空间，操作一个都会对另一个造成影响

>>> 
>>> list_1=[1,2,6,3,9,2]
>>> list_2=list_1[:]
>>> list_3=list_1
>>> list_2
[1, 2, 6, 3, 9, 2]
>>> list_3
[1, 2, 6, 3, 9, 2]
>>> list_1.sort()
>>> list_1
[1, 2, 2, 3, 6, 9]
>>> list_2
[1, 2, 6, 3, 9, 2]
>>> list_3
[1, 2, 2, 3, 6, 9]
>>> 

Python 2.7.10 (default, Oct 14 2015, 16:09:02) [GCC 5.2.1 20151010] on linux2Type "copyright", "credits" or "license()" for more information.>>> dir(list)['__add__', '__class__', '__contains__', '__delattr__', '__delitem__', '__delslice__', '__doc__', '__eq__', '__format__', '__ge__', '__getattribute__', '__getitem__', '__getslice__', '__gt__', '__hash__', '__iadd__', '__imul__', '__init__', '__iter__', '__le__', '__len__', '__lt__', '__mul__', '__ne__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__reversed__', '__rmul__', '__setattr__', '__setitem__', '__setslice__', '__sizeof__', '__str__', '__subclasshook__', 'append', 'count', 'extend', 'index', 'insert', 'pop', 'remove', 'reverse', 'sort']>>> list1=[1,2,3]>>> list2=[4,5,6]>>> list3=list1+list2>>> list3[1, 2, 3, 4, 5, 6]>>> list3*=2>>> list3[1, 2, 3, 4, 5, 6, 1, 2, 3, 4, 5, 6]>>> 3 in list3True>>> 7 in list3False>>> 7 not in list3True>>> list4["niha",[2,3],'q']
Traceback (most recent call last):  File "<pyshell#10>", line 1, in <module>    list4["niha",[2,3],'q']NameError: name 'list4' is not defined>>> list4=["niha",[2,3],'q']>>> list4['niha', [2, 3], 'q']>>> 2 in list4False>>> 2 in list[1]
Traceback (most recent call last):  File "<pyshell#14>", line 1, in <module>    2 in list[1]TypeError: 'type' object has no attribute '__getitem__'>>> 2 in list4[1]True>>> list3.count(1)2>>> list3.index(2)1>>> list3.index(4,1,10)3>>> list3.index(4,2,10)3>>> list3.reverse()>>> list3[6, 5, 4, 3, 2, 1, 6, 5, 4, 3, 2, 1]>>> >>> >>> list5=[3,7,4,9,1,8]>>> list5.sort()>>> list5[1, 3, 4, 7, 8, 9]>>> list5.so
Traceback (most recent call last):  File "<pyshell#27>", line 1, in <module>    list5.soAttributeError: 'list' object has no attribute 'so'>>> list5.sort(reverse=True)>>> list5[9, 8, 7, 4, 3, 1]>>>